Thermodynamics
2027 season
On this page(17 sections)
Thermodynamics is the study of energy moving as heat and work: why heat flows from hot to cold, how much energy it takes to warm or melt something, and why no engine can turn all of its heat into work. In the 2027 event you use that physics twice. A written test checks the ideas and the calculations, and a device you build before the tournament has to soak up energy from a heat lamp and pass it to a cup of room-temperature water while you predict how warm the water will get. The same habits win both parts: think about where the energy goes, and put numbers on it quickly.
Event format
Thermodynamics is a hybrid event with the same structure in Division B and Division C.
| Item | 2027 rules |
|---|---|
| Team size | Up to 2 |
| Time | About 50 minutes |
| Parts | Part I: written test. Part II: testing a heat-collecting device built before the tournament |
| Impound | Yes, for the device and spare parts only |
| Calculators | Up to two Class III calculators, usable at any point in the event |
| Notes | Unlimited paper notes in any form (binders, books, folders, sheet protectors, tabs); pages may be removed during the event |
| Also allowed | One device, spare parts, tools that help with setup, and prepared graphs or tables for predicting the device's result |
| Provided by the supervisor | Heat lamp setup, water bath, the 9 oz plastic cup with 100 mL of water, and the thermometer. Do not bring your own |
| Scoring | Exam Score (50) + Temperature Score (30) + Prediction Score (20) = 100 points |
Everything you impound has to be at room temperature, and you may not bring or use your own thermometer during Part II (or borrow the supervisor's). Your prediction comes from the data you collected at home and the graphs or tables you bring.
What the rules cover
The written test draws at least three questions from each topic area in the 2027 outline. The table paraphrases the outline and shows where each topic applies.
| Area | Topics | Division B | Division C | Where in this guide |
|---|---|---|---|---|
| 1. Systems and temperature | Thermodynamic systems; intensive and extensive properties; what temperature is; the zeroth law; temperature scales and conversions; heat-related units | All levels | All levels | Systems, properties and temperature |
| 2. Phases and gases | States of matter, phase transitions, phase diagrams, latent and sensible heat, the ideal gas law | All levels | All levels | Phases, latent heat and the ideal gas law |
| 3. Heat transfer | Conduction, convection and radiation; thermal conductivity; heat capacity; specific heat | All levels | All levels | Heat transfer, conductivity and heat capacity |
| 4. Processes and engines | Adiabatic, isothermal, isochoric and isobaric processes; cycles; engines; efficiency; first and second laws | All levels | All levels | Processes, cycles, engines and the laws |
| 5. History | Kelvin, Joseph Black, Joule, Carnot, Planck, Clausius, Boltzmann and Maxwell | All levels | All levels | History of thermodynamics |
| 6. Radiation and the third law | Radiant exitance, blackbody radiation, Stefan-Boltzmann law, third law | State & National | State & National | State & National: radiation and the third law |
| 7. Entropy and enthalpy | Entropy and enthalpy as quantities | Not tested | State & National | Division C, State & National: entropy and enthalpy |
The rules also limit the math. Both divisions use arithmetic with ratios, exponents and absolute value, plus area and volume of common shapes. Division B algebra stays at solving one equation for one unknown; Division C may ask for multi-step derivations with several variables. Neither division may require trigonometry or calculus. Answers are expected in metric units with sensible significant figures unless a question says otherwise.
Systems, properties and temperature
Systems and surroundings
A system is whatever you choose to study: the water in the cup, the gas in a piston, a whole engine. Everything else is the surroundings, and the boundary separates them. Systems are classified by what can cross that boundary.
| System type | Energy crosses? | Matter crosses? | Example |
|---|---|---|---|
| Open | Yes | Yes | A pot of boiling water without a lid (steam escapes) |
| Closed | Yes | No | A sealed balloon warmed in sunlight |
| Isolated | No | No | An ideal insulated, sealed container (real ones only approximate it) |
The cup of water in Part II is close to a closed system while it heats: energy arrives by radiation, conduction and convection, but very little water leaves (a small amount evaporates, which technically makes it open).
Intensive and extensive properties
An extensive property depends on how much material you have: mass, volume, internal energy, heat capacity, and (for Division C at State and National) entropy and enthalpy. Cut the sample in half and the property halves. An intensive property does not depend on amount: temperature, pressure, density, specific heat and molar mass. Cutting the sample in half leaves it unchanged.
A quick test: the ratio of two extensive properties is intensive. Mass ÷ volume gives density; heat capacity ÷ mass gives specific heat.
| Property | Intensive or extensive | Why |
|---|---|---|
| Temperature, pressure, density | Intensive | Same value in any piece of a uniform sample |
| Specific heat, molar heat capacity, specific volume | Intensive | "Per kilogram" or "per mole" removes the amount |
| Thermal conductivity, boiling point, color | Intensive | Properties of the material, not of the sample size |
| Mass, volume, number of moles | Extensive | Add up when you combine samples |
| Internal energy , enthalpy , entropy , heat capacity | Extensive | Total energy or disorder grows with the amount |
| Molar enthalpy change ( in kJ/mol) | Intensive | Divided by moles; the total for a reaction run is extensive |
State functions and path functions
The state of a simple system at equilibrium is fixed by a few state variables: for a fixed amount of a gas, any two of , and fix the third. Knowing alone is not enough; you need the amount plus two independent variables. A state function depends only on the present state, not on how the system got there: , , , internal energy , enthalpy and entropy are all state functions. So the change in a state function between two states is the same for every route, and it is zero around any complete cycle.
Heat and work are path functions. They are energy in transit, so how much of each crosses the boundary depends on the route. On a P-V diagram, two different paths between the same two states have different areas under them (different ), so they need different too, but comes out the same. A system can be described as "having" internal energy, but never as "having" heat or work.
A system is in thermodynamic equilibrium when nothing inside it changes on its own: it is in thermal equilibrium (one uniform temperature), mechanical equilibrium (uniform pressure, no unbalanced forces) and chemical and phase equilibrium. Only equilibrium states have single, well-defined values of and , which is why only equilibrium states are points on a P-V diagram.
Temperature is not heat
Temperature measures the average kinetic energy of the particles in a substance. For an ideal gas the link is exact: the average translational kinetic energy per molecule is , with J/K and in kelvin. Heat is energy in transit because of a temperature difference. An object does not "contain heat"; it contains internal energy, and heat is what crosses its boundary.
A swimming pool and a cup of tea can share a temperature while the pool holds vastly more internal energy. Temperature tells you which way heat will flow; how much flows depends on mass, specific heat and time. Heat always flows from the higher temperature to the lower one, even when the colder object holds more total internal energy (an iceberg holds more internal energy than a cup of hot coffee, yet heat flows from the coffee to the iceberg).
Internal energy is the total microscopic energy of a system: the kinetic energy of its particles (translation, rotation, vibration) plus the potential energy of the forces between them. Temperature tracks only the average kinetic part. That is why 1 kg of steam at 100 °C holds more internal energy than 1 kg of liquid water at 100 °C: same temperature, but the steam's molecules have been pulled apart against their attractions. For an ideal gas there are no attractions, so depends on temperature alone.
Absolute zero (0 K, −273.15 °C, −459.67 °F) is the temperature at which particle motion is at its minimum possible value. It is not quite "all motion stops": quantum mechanics leaves a small zero-point energy. Nothing can be colder, so negative kelvin readings in an answer choice are impossible (for ordinary systems), and the third law says even 0 K itself cannot be reached.
The zeroth law and thermometers
The zeroth law says that if A is in thermal equilibrium with C, and B is in thermal equilibrium with C, then A and B are in thermal equilibrium with each other. It is what makes a thermometer meaningful: the thermometer (C) comes to equilibrium with the water (A), and its reading tells you what any other object (B) at the same reading would be. The law was named "zeroth" because it was recognized as logically more basic only after the first and second laws already had their numbers. Calibrating a thermometer in ice water and boiling water, and reading a thermometer placed in a cup of tea, are the standard examples of the zeroth law at work.
Every thermometer uses a thermometric property: something that changes in a known, repeatable way with temperature. It is calibrated against fixed points such as the ice point and steam point of water or, more precisely, the triple point of water (273.16 K).
| Thermometer | Property that changes | Notes |
|---|---|---|
| Liquid-in-glass (mercury or colored alcohol) | Volume of the liquid | Mercury expands very uniformly, stays liquid from −39 °C to 357 °C, does not wet glass and is easy to see; alcohol (ethanol freezes at −114 °C) works far below mercury's −39 °C freezing point, so it is used in very cold places |
| Bimetallic strip (dial thermometers, old thermostats) | Different expansion of two bonded metals | When heated, the strip bends toward the metal that expands less |
| Constant-volume gas thermometer | Pressure of a fixed volume of gas () | Nearly independent of which gas is used; it defines the absolute scale and points toward absolute zero |
| Thermocouple | Voltage at the junction of two different metals (Seebeck effect) | Wide range, cheap, rugged; measures a temperature difference between two junctions |
| Resistance thermometer (RTD) | Electrical resistance of platinum, which rises with | Very accurate and stable |
| Thermistor | Resistance of a semiconductor, which usually falls as rises | Very sensitive over a narrow range; used in digital thermometers |
| Infrared thermometer, pyrometer | Thermal radiation emitted by the surface | No contact; needs the surface's emissivity |
A liquid-in-glass thermometer works only because the liquid expands much more than the glass bulb holding it. Plunge one into hot water and the reading first dips slightly: the glass warms and expands before heat reaches the liquid, so the bulb's volume grows first; then the liquid catches up and the column rises. A good thermometer liquid expands uniformly (so the scale is linear), stays liquid over the range needed, and is easy to see.
The earliest instrument was Galileo's thermoscope (around 1600): air trapped in a glass bulb above a column of water, so the water level moved as the air expanded or contracted. It showed temperature changes but had no numbered scale and also responded to air pressure. Sealed liquid-in-glass thermometers with scales followed in the 1600s and 1700s. A thermometer measures temperature, not internal energy or heat, so "a thermometer measures internal energy" is false. Calorimeters, not thermometers, are the devices that measure heat.
Temperature scales and conversions
Celsius and Fahrenheit are relative scales with arbitrary zeros. Kelvin and Rankine are absolute scales that put zero at absolute zero. One kelvin is the same size as one Celsius degree, and one Rankine degree is the same size as one Fahrenheit degree.
The direct routes save steps on a test: ; ; ; .
ReferenceLandmark temperatures on four scales· 10 rows
Values at 1 atm. Body temperature is the conventional 37 °C.
No rows match.
| Landmark | K | °C | °F | °R |
|---|---|---|---|---|
| Absolute zero | 0 | −273.15 | −459.67 | 0 |
| Liquid nitrogen boils | 77.4 | −195.8 | −320.4 | 139.3 |
| Dry ice sublimes | 194.65 | −78.5 | −109.3 | 350.4 |
| Celsius and Fahrenheit agree | 233.15 | −40 | −40 | 419.67 |
| Fahrenheit zero | 255.37 | −17.78 | 0 | 459.67 |
| Water freezes (ice point) | 273.15 | 0 | 32 | 491.67 |
| Triple point of water | 273.16 | 0.01 | 32.02 | 491.69 |
| Room temperature (typical) | 293–298 | 20–25 | 68–77 | 528–537 |
| Human body | 310.15 | 37 | 98.6 | 558.27 |
| Water boils | 373.15 | 100 | 212 | 671.67 |
How to read it: the Kelvin and Celsius columns always differ by 273.15, and the Rankine and Fahrenheit columns by 459.67. Between the ice point and the steam point there are 100 Celsius degrees and 180 Fahrenheit degrees, which is where the factor 1.8 (= 9/5) comes from.
Worked exampleWhere two scales agree, and a doubled temperature
Set in : , so . The two scales agree only at −40°.
"Double the temperature of an object at 40 °C" means doubling the absolute temperature: K (353 °C), not 80 °C.
A rise from 35 °F to 75 °F is a change of 40 F°, which is C° (a difference, so no offset).
Some history of the scales is fair game because it explains their fixed points. Daniel Fahrenheit (1724) set 0 °F at the temperature of an ice-water-salt (brine) mixture and used roughly human body temperature as his upper reference (about 96 on his original scale); water then froze at 32 and boiled at 212. Anders Celsius (1742) originally put 100 at the freezing point and 0 at the boiling point; the scale was reversed shortly after his death and was long called "centigrade". Kelvin's absolute scale (1848) and William Rankine's Fahrenheit-sized absolute scale (1859) both start at absolute zero. On a Celsius thermometer the degree is the same size as the kelvin, which is why scientific work pairs those two. Neither scale is more "accurate"; a Fahrenheit degree is just a smaller step.
Since 2019 the kelvin has been defined by fixing the numerical value of the Boltzmann constant. Before that it was defined through the triple point of water, 273.16 K. Older tests may phrase it either way.
Heat-related units
| Unit | Meaning | Value in SI |
|---|---|---|
| Joule (J) | SI unit of energy, heat and work | 1 J = 1 N·m |
| Calorie (cal) | Heat to warm 1 g of water by about 1 °C | 4.184 J (the thermochemical calorie; the older "IT" calorie is 4.1868 J, which is why water's appears as both 4.184 and 4.186 J/(g·°C); use whatever value the test gives) |
| Food Calorie (Cal, kcal) | 1,000 calories | 4,184 J |
| British thermal unit (BTU) | Heat to warm 1 lb of water by 1 °F | about 1,055 J |
| Watt (W) | Power: energy per second | 1 J/s |
| Kilowatt-hour (kWh) | Energy at 1 kW for 1 hour | 3.6 × 10⁶ J |
Energy is the capacity to do work or to transfer heat. Work is energy transferred when a force acts through a distance (for a gas, when its volume changes against a pressure); heat is energy transferred because of a temperature difference. Both are measured in joules, and neither is "stored" in an object; what an object stores is internal energy.
Related quantities carry their own units: specific heat in J/(kg·K) or J/(g·°C), latent heat in J/kg, thermal conductivity in W/(m·K), and pressure in pascals (1 kPa = 1,000 Pa; 1 atm = 101,325 Pa).
| More units you will meet | Value |
|---|---|
| Joule in SI base units | 1 J = 1 kg·m²/s² (= 1 N·m = 1 W·s = 1 Pa·m³) |
| erg and dyne (cgs units) | 1 erg = 1 dyne·cm = 10⁻⁷ J; 1 dyne = 1 g·cm/s² = 10⁻⁵ N |
| Foot-pound (ft·lbf) | 1.356 J; the mechanical equivalent of heat is about 778 ft·lbf per BTU (Joule's own 1849 result was about 772) |
| Liter-atmosphere (L·atm) | 101.3 J (useful when comes out in L·atm) |
| Therm (natural-gas bills) | 100,000 BTU ≈ 105.5 MJ |
| Ton of refrigeration | 12,000 BTU/h ≈ 3.52 kW of heat removal |
| Horsepower (hp) | about 746 W |
| BTU per hour | 0.293 W |
| Electron-volt (eV) | 1.602 × 10⁻¹⁹ J |
| Pressure | 1 atm = 101.325 kPa = 760 mmHg (torr) = 14.7 psi = 1.01325 bar |
| Volume and water mass | 1 L = 1,000 cm³ = 10⁻³ m³; 1 US gallon = 3.785 L; 1 mL of water ≈ 1 g, so 1 L of water ≈ 1 kg |
| Mass and length | 1 lb = 0.4536 kg; 1 in = 2.54 cm; 1 ft = 0.3048 m |
ReferenceConstants for the binder· 11 rows
No rows match.
| Constant | Value |
|---|---|
| Gas constant | 8.314 J/(mol·K) = 0.08206 L·atm/(mol·K) = 1.987 cal/(mol·K) = 62.36 L·torr/(mol·K) |
| Boltzmann constant | 1.380649 × 10⁻²³ J/K (exact since 2019) |
| Avogadro's number | 6.022 × 10²³ mol⁻¹ |
| Stefan-Boltzmann constant | 5.67 × 10⁻⁸ W/(m²·K⁴) |
| Wien's constant | 2.898 × 10⁻³ m·K |
| Planck's constant | 6.626 × 10⁻³⁴ J·s |
| Speed of light | 3.00 × 10⁸ m/s |
| Molar volume of an ideal gas | 22.4 L/mol at 0 °C and 1 atm; 24.5 L/mol at 25 °C and 1 atm |
| Water: , , | 4,186 J/(kg·K) (1 cal/(g·°C)); 334 kJ/kg (6.01 kJ/mol); 2,256 kJ/kg (40.7 kJ/mol) |
| Ice and steam: | about 2,100 and 2,000 J/(kg·K) |
| Solar constant | about 1,361 W/m² at the top of Earth's atmosphere |
The units also tell you what a quantity is. Heat capacity is J/K (or BTU/°R, BTU/°F, cal/°C); specific heat is J/(kg·K); entropy is J/K, the same units as heat capacity; molar quantities add "/mol". Emissivity is a pure ratio with no units. An answer that comes out in the wrong units signals a formula used wrongly.
Worked exampleMixing units in one problem
How many °F does 75 cal raise 10 g of water? C°, which is F°.
A 1,000 W kettle heats 0.200 kg of water from 20 °C to 100 °C: J, so s (if no heat is lost).
A 120 W bulb on for 5.0 h uses kWh J.
Thermal expansion
Most materials expand when heated because their particles vibrate with larger amplitude and, since the forces between atoms are lopsided (easier to pull apart than to push together), the average spacing grows. Expansion is the property most thermometers use, and it is why bridges have expansion joints and power lines sag on hot days.
Formula #2Linear, area and volume expansion
= coefficient of linear expansion (1/K or 1/°C, the same number), = coefficient of volume expansion, , , = starting size. can be in K or °C.
Why : a cube of side becomes on each side, so its volume becomes because the squared and cubed terms in a tiny are negligible. A hole in a plate expands exactly as if it were filled with the plate material, so heating a metal lid loosens it on a glass jar.
| Solid | (per K) |
|---|---|
| Aluminum | 23 × 10⁻⁶ |
| Brass | 19 × 10⁻⁶ |
| Copper | 17 × 10⁻⁶ |
| Steel or iron | 11–13 × 10⁻⁶ |
| Ordinary glass | about 9 × 10⁻⁶ |
| Borosilicate (Pyrex) glass | 3.3 × 10⁻⁶ |
| Invar (nickel-iron alloy) | about 1 × 10⁻⁶ |
| Liquid or gas | (per K) |
|---|---|
| Water at 20 °C | 2.1 × 10⁻⁴ |
| Mercury | 1.8 × 10⁻⁴ |
| Gasoline | about 9.5 × 10⁻⁴ |
| Ethanol | 1.1 × 10⁻³ |
| Air (ideal gas at 20 °C) | ≈ 3.4 × 10⁻³ |
How to use it: liquids expand roughly several to a hundred times more than solids, and gases more still. Because a container expands too, a liquid's apparent expansion is its own minus the container's, which is one reason liquid expansion is harder to measure than solid expansion. When a solid is heated its mass stays the same while its volume grows, so its density falls.
Worked exampleA steam pipe
A steel pipe ( /K) is 36.0 m long at 15 °C and carries steam at 155 °C.
m, so the pipe grows 60 mm. Expansion loops or joints must absorb it.
Longer objects expand more for the same , because is proportional to .
Worked exampleHow hot for 1.5% longer?
Brass, /K: K. Starting at 25 °C, the rod must reach about 815 °C.
A bimetallic strip bonds two metals with different , such as brass and steel. On heating, the high- metal lengthens more, so the strip curls with the high- metal on the outside of the curve; on cooling it curls the other way. Old thermostats, dial thermometers and some circuit breakers use this.
Key factsWater's odd expansion
- Liquid water contracts as it warms from 0 °C to about 4 °C ( in that range), so its density is greatest, 1.000 g/cm³, near 4 °C.
- Ice (0.917 g/cm³) is less dense than liquid water, so ice floats, water expands by about 9% when it freezes, and freezing pipes burst.
- Lakes freeze from the top down: the 4 °C water sinks to the bottom and stays liquid under the ice, which is why fish survive winter.
Phases, latent heat and the ideal gas law
Key factsPhases and gases in one minute
- on slopes, on plateaus; water = 334 kJ/kg, = 2,256 kJ/kg.
- Melting, vaporizing and subliming absorb heat; freezing, condensing and deposition release it.
- Boiling: vapor pressure = outside pressure. Higher altitude → lower boiling point.
- Triple point: three phases coexist. Critical point: liquid and gas become identical. Water's melting line slopes backward.
- with in kelvin; ; .
Phases and phase transitions
Solids hold their particles in fixed positions, so they keep their shape and volume; liquids let particles slide past one another, so they keep their volume but take the container's shape; gases let particles move freely, so they fill whatever container they are in. Plasma, a gas so hot that electrons are stripped from atoms, conducts electricity and is the most common state of visible matter in the universe (stars). A Bose-Einstein condensate, formed near absolute zero, is a fifth state seen only in labs. Which phase a substance is in depends on the competition between particle kinetic energy (set by temperature) and intermolecular attractions (and on pressure, which pushes particles together).
| Transition | Direction | Heat | Everyday example |
|---|---|---|---|
| Melting (fusion) / freezing (solidification) | Solid ↔ liquid | Absorbed on melting, released on freezing | Ice melting in a drink; farmers spray crops so the freezing water releases heat |
| Vaporization (boiling, evaporation) / condensation | Liquid ↔ gas | Absorbed on vaporizing, released on condensing | Sweat and hand sanitizer cooling skin; steam burns are worse than boiling-water burns |
| Sublimation / deposition | Solid ↔ gas | Absorbed on sublimating, released on depositing | Dry ice and camphor sublime at room conditions; frost forms by deposition |
For almost every substance the density order is solid > liquid > gas, because particles pack most tightly in the solid. Water is the famous exception: ice is less dense than liquid water (0.917 versus 1.000 g/cm³) because hydrogen bonds hold the ice crystal in an open hexagonal framework. A gas is roughly a thousand times less dense than its liquid; that is why a gas is easy to compress and a liquid or solid is not.
Every forward transition toward more particle freedom (melting, vaporizing, subliming) is endothermic () and raises entropy (the spread of energy over more possible arrangements; Division C covers it in detail); every reverse transition is exothermic and lowers the substance's entropy.
Evaporation is vaporization from the surface, at any temperature below the boiling point. Boiling is vaporization throughout the liquid, with bubbles of vapor forming inside it, and it happens when the liquid's vapor pressure equals the pressure above it. Vaporization is the umbrella term for both. Evaporation cools what is left behind, because the fastest molecules escape and the average kinetic energy of those remaining drops. That is why sweating, a wet cloth in a breeze and alcohol-based hand sanitizer all cool the skin.
Vapor pressure is the pressure exerted by a liquid's own vapor in equilibrium with it. It rises steeply with temperature and does not depend on how much liquid there is. Changing the outside pressure therefore changes the boiling point:
- At high altitude the air pressure is lower, so water boils below 100 °C (about 95 °C in Denver, about 70 °C on top of Mount Everest), and food takes longer to cook.
- A pressure cooker raises the pressure to about 2 atm absolute, so water boils near 120 °C and food cooks faster.
- A liquid boils at room temperature in a vacuum chamber, and an inverted flask of hot water starts boiling again when cold water on the outside condenses the vapor inside and lowers the pressure.
Phase changes do not always happen on schedule. A very pure, undisturbed liquid can be supercooled below its freezing point, or superheated above its boiling point, until a disturbance or seed crystal triggers the change. During any phase change at equilibrium both phases coexist, and the rate of melting equals the rate of freezing (or vaporizing equals condensing).
Sensible and latent heat
Sensible heat changes temperature without changing phase. Latent heat changes phase without changing temperature. During melting or boiling the energy goes into breaking intermolecular attractions rather than into faster particle motion, so the thermometer reading stays flat.
Formula #3Sensible heat
in J, in kg, in J/(kg·K), in K or °C (same size step). For water, J/(kg·K), or 4.186 J/(g·°C).
Formula #4Latent heat
in J/kg. For water, J/kg (fusion) and J/kg (vaporization at 100 °C).
Show worked exampleHide worked example
Worked exampleIce to warm water
Take 0.200 kg of ice at 0.0 °C to liquid water at 70.0 °C.
Melt: J.
Warm: J.
Total: about J, or 125 kJ (an answer choice of "130 kJ" is the nearest two-figure value).
More than half the energy went into melting, while the temperature did not move at all.
A heating curve plots temperature against heat added. Sloped segments are sensible heating, with slopes set by for each phase; flat segments are phase changes, with lengths set by . Because for water is almost seven times , the boiling plateau is far longer than the melting plateau.
TipFlat means phase change
On a heating or cooling curve, a flat segment is latent heat; a sloped segment is . If a question adds heat during a phase change, check whether the change finishes before you compute a temperature rise.

Reading a heating curve: the x axis is heat added (or time, at a steady heating rate). On a sloped segment the particles speed up, so average kinetic energy and temperature rise; on a plateau the added energy raises the potential energy of the particles as attractions are broken, and the kinetic energy stays the same. A steeper slope means a smaller heat capacity (). A cooling curve is the same graph run backwards, with plateaus where the substance releases its latent heat.
| Substance | Melting point (°C) | (kJ/kg) | Boiling point (°C) | (kJ/kg) |
|---|---|---|---|---|
| Water | 0 | 334 | 100 | 2,256 |
| Ethanol | −114 | 108 | 78 | 855 |
| Ammonia | −78 | 332 | −33 | 1,370 |
| Lead | 327 | 23 | 1,750 | 871 |
| Aluminum | 660 | 397 | 2,470 | 10,500 |
| Mercury | −39 | 11 | 357 | 296 |
| Nitrogen | −210 | 25.7 | −196 | 199 |
In chemistry units, latent heats are molar enthalpies: for water kJ/mol and kJ/mol at 100 °C (44.0 kJ/mol at 25 °C). Convert with the molar mass: kJ/g. Vaporization always takes far more energy than melting because the molecules must be separated completely rather than just loosened.
Worked exampleIce at −10 °C to steam at 110 °C (50.0 g)
Warm the ice: J.
Melt it: J.
Warm the water from 0 to 100 °C: J.
Boil it: J.
Warm the steam from 100 to 110 °C: J.
Total: about J (152 kJ). Boiling alone is about three-quarters of it. Five steps, each with its own or .
Worked exampleWill all the ice melt?
100 g of ice at 0 °C is dropped into 200 g of water at 25 °C.
Heat the water can give up cooling to 0 °C: J.
Heat needed to melt all the ice: J.
The water runs out first, so the mixture ends at 0 °C with ice left over: kg melts, leaving about 37 g of ice.
Always compare these two quantities before writing a single energy-balance equation; otherwise you can get an impossible answer like a final temperature below 0 °C for liquid water.
Worked exampleSteam versus ice
10.0 g of steam at 100 °C meets 50.0 g of ice at 0 °C. Condensing the steam releases J and cooling that water to 0 °C releases J, for at most 26,750 J. Melting all the ice needs J, so all the ice melts and the mixture ends above 0 °C.
Energy balance (all 60.0 g end as water at ): .
, so °C.
Steam's huge latent heat is also why a steam burn is far worse than a burn from water at the same 100 °C.
Phase diagrams
A phase diagram maps which phase is stable at each pressure and temperature. The lines are coexistence curves where two phases are in equilibrium. They meet at the triple point, where all three coexist (for water, 0.01 °C and about 612 Pa). The liquid-vapor line ends at the critical point, beyond which liquid and gas are no longer distinct (a supercritical fluid).
Read a diagram by asking two things: which region holds the given point, and which line a process crosses. Moving right at constant pressure is heating; moving up at constant temperature is compressing. Below the triple-point pressure a solid sublimates directly to vapor, which is why dry ice (CO₂) never melts at 1 atm.
| Feature | Water | Carbon dioxide |
|---|---|---|
| Triple point | 273.16 K (0.01 °C), 611.7 Pa (0.006 atm, 4.58 mmHg) | 216.6 K (−56.6 °C), 5.11 atm (518 kPa) |
| Critical point | 647.1 K (374 °C), 22.06 MPa (218 atm) | 304.1 K (31.0 °C), 7.38 MPa (72.8 atm) |
| Solid-liquid line | Slopes left (negative): pressure lowers the melting point | Slopes right (positive): pressure raises the melting point |
| At 1 atm | Melts at 0 °C, boils at 100 °C | Sublimes at −78.5 °C |
The names of the parts are tested directly:
- Fusion (melting) curve: solid-liquid boundary. Vaporization curve: liquid-gas boundary, which is also the vapor-pressure curve; its intersection with the 1 atm line is the normal boiling point. Sublimation curve: solid-gas boundary below the triple point. Near the triple point the sublimation curve is steeper than the vaporization curve, because subliming takes more latent heat (fusion plus vaporization).
- Triple point: the single pressure and temperature where solid, liquid and gas coexist in equilibrium.
- Critical point: the end of the liquid-gas line. Above the critical temperature no amount of pressure can liquefy the gas; above both the critical temperature and pressure the substance is a supercritical fluid, which flows like a gas but dissolves things like a liquid (supercritical CO₂ decaffeinates coffee). At the critical point the liquid and vapor densities become equal.
- A point on a line has two phases in equilibrium; a point in a region has one.
- Gibbs phase rule: , where is the number of components (1 for pure water), the number of phases present and the degrees of freedom (how many of and you can change independently while keeping the same phases). In a one-phase region (an area); on a two-phase line (choose and is fixed); at the triple point (a single point). That is why a pure substance cannot have four phases coexisting.
Why water's melting line slopes backwards: ice is less dense than liquid water, so squeezing ice favors the denser liquid, and the melting point drops as pressure rises (by about 0.0075 °C per atmosphere). For almost every other substance the solid is denser and the line slopes forward. If a question just says "a substance" and asks whether raising pressure raises or lowers its melting point, the honest answer is that it depends on whether the solid or the liquid is denser.
The same physics looks different on a pressure-volume diagram. Compress a gas slowly at a fixed temperature below its critical temperature: its pressure rises along a hyperbola-like isotherm until droplets appear, then stays perfectly flat (the vapor pressure) while gas turns to liquid, then shoots up steeply once only liquid is left, because liquids barely compress. The ends of all those flat segments trace out a dome-shaped saturation curve: its left side is the saturated-liquid line, its right side the saturated-vapor line, and inside the dome liquid and vapor coexist. The top of the dome is the critical point, where the critical isotherm has no flat part, only a horizontal inflection. Isotherms above the critical temperature never cross the dome; far above it they approach the ideal-gas hyperbolas = constant.
The Clausius-Clapeyron relation
The slope of any coexistence line is set by the latent heat and by the volume change of the transition. This is the Clapeyron equation; it explains both water's backward melting line and how quickly vapor pressure rises with temperature.
Formula #5Clapeyron and Clausius-Clapeyron equations
Left: slope of any phase boundary; = latent heat per kg (J/kg), in K, = change in specific volume (m³/kg, volume per kg = 1/density) going to the higher-entropy phase. Right: liquid-vapor (or solid-vapor) line, treating the vapor as an ideal gas and neglecting the liquid's volume; = molar latent heat (J/mol), J/(mol·K). and can be in any one pressure unit.
Show 2 worked examplesHide worked examples
Worked exampleSlope of water's melting line
Ice density 917 kg/m³, water 1000 kg/m³: m³/kg (melting shrinks the volume).
Pa/K, about −13.5 MPa/K or −133 atm/K.
Inverted: the melting point drops about 0.0075 K for each extra atmosphere. The negative sign is the backward slope.
Worked exampleVapor pressure of water at 90 °C
Known point: 101.3 kPa at 373.15 K; J/mol.
.
kPa (tables give 70.2 kPa).
Run backwards, the same equation finds a latent heat from two measured vapor pressures: .
Trouton's rule (Division C, State & National, since it uses entropy) is a handy check: for many liquids the molar entropy of vaporization at the normal boiling point is about 85 to 88 J/(mol·K), so in J/mol. Water (109 J/(mol·K)) is higher because hydrogen bonding orders the liquid.
The ideal gas law
The ideal gas model treats particles as points that collide elastically and do not attract one another. Real gases behave this way at low pressure and high temperature. The ideal gas law combines Boyle's, Charles's and Gay-Lussac's laws with Avogadro's principle.
Formula #6Ideal gas law
in Pa, in m³, in mol, J/(mol·K), in kelvin. For a fixed amount of gas, .
| Law | Held constant | Relationship |
|---|---|---|
| Boyle | , | |
| Charles | , | |
| Gay-Lussac | , | |
| Avogadro | , |
Worked exampleA heated, sealed container
A rigid container holds air at 20 °C and 100 kPa. It is warmed to 50 °C. Volume is fixed, so .
K, K.
kPa.
Using Celsius would have given 250 kPa, which is wrong.
Worked exampleMoles from mass
80 g of helium (4.0 g/mol) is 20 mol; 400 g of argon (40 g/mol) is 10 mol. The lighter sample has more particles, so at the same and it fills twice the volume.
Worked exampleChoosing the right R
0.50 mol of gas at 25 °C (298.15 K) and 2.00 atm. With L·atm/(mol·K): L.
In SI: m³, the same 6.1 L. Mixing units (atm with 8.314) is the classic error.
For a mixture, add the moles of every gas first (Dalton's law: each gas contributes a partial pressure , and the partial pressures add to the total).
The gas laws hide a trap in the word "double". Doubling the volume of a gas at constant temperature halves its pressure (Boyle). Doubling the Celsius temperature of a rigid container of gas at 20 °C (to 40 °C) raises its pressure by only times, "less than double", because the pressure is proportional to the kelvin temperature.
Two more gas-law tools. Density form: since , the ideal gas law becomes , so a measured density gives the molar mass (air at 1 atm and 20 °C: kg/m³). Standard conditions: "STP" traditionally means 0 °C and 1 atm, where one mole of ideal gas occupies 22.4 L; the current IUPAC standard is 0 °C and 1 bar, giving 22.7 L. Use the definition the question states.
Extrapolating to absolute zero. Plot the volume of any gas at constant pressure (or its pressure at constant volume) against Celsius temperature and you get a straight line. Lines for every gas, at every pressure, extend back to meet zero volume or pressure at the same point, −273.15 °C. Real gases liquefy long before, but this extrapolation is how absolute zero was first estimated and why the kelvin scale starts there.
Kinetic theory: what temperature and pressure mean
The kinetic molecular theory pictures a gas as a huge number of tiny particles in random motion, colliding elastically with each other and the walls, with no forces between collisions. Pressure is the average force per area of molecules bouncing off the walls. Temperature is proportional to the average translational kinetic energy of the molecules:
Formula #7Kinetic energy and molecular speed
in K; = molar mass in kg/mol; = mass of one molecule in kg. Total translational KE of moles: .
Show worked exampleHide worked example
Worked exampleSpeeds of nitrogen and helium
N₂ at 300 K: m/s.
He at 300 K: m/s.
Same temperature, same average KE, but the lighter helium atoms move times faster.
Quadruple the kelvin temperature and doubles. Double both and of a sample and quadruples (), so doubles.
The curve is lopsided, so its three common "average" speeds come in a fixed order: most probable speed < mean speed < rms speed. The tail of fast molecules explains evaporation below the boiling point and why reactions speed up when warmed. Maxwell derived this distribution around 1860 and Boltzmann generalized it. The same dependence gives Graham's law: the rate at which a gas effuses through a tiny hole is inversely proportional to the square root of its molar mass, , so helium (4 g/mol) effuses times as fast as oxygen (32 g/mol).
Heat capacities of an ideal gas
Each independent way a molecule can store energy (a degree of freedom) holds on average (the equipartition theorem). A monatomic gas (He, Ne, Ar) has only three translational degrees of freedom. A diatomic gas (N₂, O₂, air) at room temperature adds two rotations, for five. Vibrations only switch on at high temperature.
| Gas type | (per mole) | ||
|---|---|---|---|
| Monatomic | = 12.5 J/(mol·K) | = 20.8 J/(mol·K) | 5/3 ≈ 1.67 |
| Diatomic, room temperature | = 20.8 J/(mol·K) | = 29.1 J/(mol·K) | 7/5 = 1.40 |
is always larger than (by exactly per mole for an ideal gas, Mayer's relation) because at constant pressure the gas expands as it warms, so part of the heat goes into work on the surroundings instead of into internal energy. Because an ideal gas's internal energy depends only on temperature, for any process, not only constant-volume ones. For solids, the molar heat capacity approaches about ≈ 25 J/(mol·K) at ordinary temperatures (the Dulong-Petit law), which is why metals with heavier atoms have smaller specific heats per gram.
Real gases
Real gases deviate from at high pressure (molecules take up a real fraction of the volume) and at low temperature near condensation (attractions pull molecules together and lower the pressure). The ideal gas law works best at low pressure, low density and high temperature relative to the critical point. The van der Waals equation corrects both effects:
where measures the attractions (larger for easily liquefied gases) and is the volume excluded by the molecules themselves. Below its critical temperature a gas can be liquefied by pressure alone.
Heat transfer, conductivity and heat capacity
Key factsHeat transfer in one minute
- Conduction: contact, . Convection: moving fluid, . Radiation: no medium, .
- Insulators trap still air; R-values add in series.
- Good absorbers are good emitters; shiny surfaces are poor at both.
- Calorimetry: heat lost = heat gained; the final temperature is a heat-capacity-weighted average.
- Newton's law of cooling: the temperature difference decays exponentially.
Heat moves by three mechanisms, and tests often describe a situation in one sentence and ask which one dominates. All three matter for the Part II device.
Conduction
Conduction is energy passed through a material by particle collisions and, in metals, by free electrons. The material itself does not move. The rate through a slab follows Fourier's law.
Formula #8Conduction through a slab
in W, = thermal conductivity in W/(m·K), = area in m², = temperature difference across the slab in K, = thickness in m.

Thermal conductivity is a material property. Approximate room-temperature values: copper about 400, aluminum about 240, glass about 1, water about 0.6, wood about 0.1 to 0.2, polystyrene foam about 0.03, and still air about 0.026 W/(m·K). Foams insulate well because they trap small pockets of air that cannot circulate.
Worked exampleDoubling insulation
A foam panel ( W/(m·K)) of area 0.050 m² has 20 K across it.
At 0.010 m thick: W.
At 0.020 m thick: 1.5 W. Doubling thickness halves the loss.
Common pitfallWhy metal feels colder
A steel block and a wooden block that have sat in the same room are at the same temperature. Steel feels colder because its high conductivity pulls heat out of your hand faster, not because it is cooler. A brass doorknob feels colder than a glass one for the same reason: glass has the lower conductivity.
The rate of conduction depends on the material (), the area, the temperature difference and the thickness; it does not depend on the mass of the slab. Metals conduct well because free electrons carry energy quickly; nonmetals rely on lattice vibrations alone. Gases conduct poorly because their molecules are far apart, which is why trapped air is the working part of almost every insulator: foam, fiberglass, down, wool, double-pane windows, and fresh snow (snow insulates better than solid ice). Conductivity changes somewhat with temperature, so tabulated values are for a stated temperature.
ReferenceThermal conductivity of common materials· 10 rows
Approximate values near room temperature, W/(m·K). Ranges reflect different grades and sources.
No rows match.
| Material | Material | ||
|---|---|---|---|
| Diamond | 900–2,300 | Concrete | 0.8–1.7 |
| Silver | 429 | Ice (0 °C) | 2.2 |
| Copper | 400 | Water | 0.6 |
| Aluminum | 237 | Brick | 0.4–0.8 |
| Brass | about 110 | Human tissue | 0.2–0.5 |
| Iron | 80 | Wood | 0.1–0.2 |
| Steel (carbon) | about 50 | Snow (fresh) | 0.05–0.25 |
| Stainless steel | about 15 | Fiberglass, wool | about 0.04 |
| Lead | 35 | Polystyrene foam | about 0.03 |
| Glass | about 1 | Air (still) | 0.026 |
Thermal resistance and R-values
Builders describe insulation by its thermal resistance, the thickness divided by the conductivity. Resistances of layers stacked in series simply add, like resistors in series, which makes multi-layer walls easy.
Formula #9R-value and layered walls
in m²·K/W (SI); US R-values are in ft²·°F·h/BTU, and 1 SI unit = 5.678 US units (so US R-19 ≈ SI 3.3). is the U-factor (overall heat-transfer coefficient), in W/(m²·K). A higher R (lower U) means better insulation.
Show 3 worked examplesHide worked examples
Worked exampleA two-layer wall
0.10 m of fiberglass (): . Plus 0.020 m of wood (): .
m²·K/W. For a 10 m² wall with 20 K across it: W.
Almost all of the resistance is the insulation, so the thin wood layer barely matters.
Worked exampleA roof given a US R-value
An 8 m × 12 m roof is rated R-28 (US), which is m²·K/W. Inside 20 °C, outside −4 °C.
W.
Worked exampleComparing insulation
Old: 25 mm thick, , so . New: 30 mm, , so . The new layer loses times as much heat, 25% less.
Thickness and conductivity both matter: a 1 mm sheet of fiberglass () out-insulates a 1 m block of aluminum ().
Convection
Convection carries energy by the bulk motion of a fluid. Warmed fluid expands, becomes less dense and rises; cooler fluid sinks to replace it. In natural (free) convection density differences alone drive the flow; in forced convection a fan, pump or wind does. Convection needs a fluid, so it cannot happen through a solid or across a vacuum, and it happens only in liquids and gases.
Examples tests use: a pot of water heated from below (circulating convection cells); a room radiator or a space heater with a fan; a forced-air furnace blowing warm air through ducts; air conditioning (cold air sinks, so vents work well high up, and heaters work well low down); a hand held above a candle burns while one beside it does not (hot gases rise); sea breezes by day (land warms faster, air rises over it and cooler sea air flows in) and land breezes at night; blood carrying heat around the body; mantle convection and magma; boiling. Wind chill is forced convection: moving air strips away the warm layer next to your skin.
Formula #10Newton's law of convection
= convective heat-transfer coefficient in W/(m²·K), = surface area in m², = surface temperature, = fluid temperature far from the surface.
| Situation | Typical , W/(m²·K) |
|---|---|
| Free convection, gases (still air) | 2–25 |
| Free convection, liquids | 10–1,000 |
| Forced convection, gases (fan, wind) | 25–250 |
| Forced convection, liquids | 100–20,000 |
| Boiling or condensing | 2,500–100,000 |
The coefficient is not a material property like : it depends on the fluid, its speed, the shape of the surface and the temperature difference, which is why forced flow and phase change give much larger values.
Worked exampleConvection from a hot pipe
A pipe 20 mm in diameter has a surface at 60 °C in 20 °C still air with W/(m²·K). Surface area per meter of length: m².
W per meter of pipe.
A fan raises , and the loss rises in proportion to .
Radiation
Thermal radiation is energy carried by electromagnetic waves, mostly infrared at everyday temperatures. It needs no medium, which is how sunlight crosses space and how a heat lamp warms your hand from half a meter away. Every object above absolute zero radiates, and hotter objects radiate much more strongly. How well a surface absorbs radiation is described by its absorptivity; a good absorber is also a good emitter at the same wavelength. Matte black surfaces absorb most visible and infrared light; shiny metal surfaces reflect most of it.
When radiation strikes a surface, each part of it is absorbed, reflected or transmitted, and the three fractions add to 1: absorptivity + reflectivity + transmissivity = 1. For an opaque surface, transmissivity is 0, so a good reflector is a poor absorber. Kirchhoff's law of thermal radiation adds that, at a given wavelength and temperature, a surface's emissivity equals its absorptivity: good absorbers are good emitters, and good reflectors (shiny, low-emissivity surfaces) are poor emitters. A black matte can of hot water cools faster than a shiny one at the same temperature, and a black surface in sunlight warms faster.
| Surface | Emissivity (approximate) |
|---|---|
| Ideal blackbody | 1 (by definition) |
| Human skin | 0.95–0.98 |
| Water, ice | about 0.96 |
| Matte black paint | 0.95–0.98 |
| Brick, concrete | about 0.9 |
| Oxidized steel | about 0.8 |
| Polished aluminum | about 0.05 |
| Polished silver or gold | 0.02–0.03 |
Reflective "radiant barrier" insulation and emergency blankets therefore have high reflectivity and low emissivity. A vacuum flask (thermos) combines all three ideas: the vacuum between its double walls stops conduction and convection, and the silvered walls cut radiation. The greenhouse effect is a radiation story: sunlight (mostly visible and near-infrared, from a hot source) passes through glass or the atmosphere, the warmed ground re-emits long-wave infrared, and glass or greenhouse gases absorb much of that infrared and send part of it back down (a real glass greenhouse stays warm mostly because it blocks convection, so the atmospheric effect is the purer radiation example). Spacecraft and satellites, surrounded by vacuum, can shed waste heat only by radiation from radiator panels.
TipPicking the mechanism
Heat crossing empty space or reaching you with no contact: radiation. Something visibly flowing (air rising over a radiator, water circulating in a pot): convection. Heat passing through a solid or a still layer: conduction.
| Situation | Main mechanism |
|---|---|
| Sunlight warming Earth; warmth felt from a campfire or heat lamp | Radiation |
| Feeling warmth on a sunny beach | Radiation |
| Iron skillet handle getting hot; a spoon in hot soup | Conduction |
| Ice feeling cold in your hand; touching a cold metal railing | Conduction |
| Hot air rising above a flame or radiator; forced-air heating | Convection |
| Water heating in a pot from below | Convection (conduction through the pot bottom) |
| Sweating, hand sanitizer drying | Evaporation (latent heat carried away) |
Tests sometimes list evaporation as a fourth cooling route; strictly it is mass transfer that carries latent heat, usually helped by convection. "Induction" is not a heat-transfer mechanism.
Heat capacity, specific heat and calorimetry
Heat capacity is the energy an object needs per kelvin of warming; for a single material . A material with high specific heat warms slowly for a given energy input, which is why water is such a good heat store and why 100 mL of water in Part II needs about 419 J for every 1 °C of rise ( J/(kg·K)).
ReferenceSpecific heats of common materials· 10 rows
Near room temperature unless stated. Divide by 1,000 for J/(g·°C); divide J/(g·°C) by 4.186 for cal/(g·°C).
No rows match.
| Material | , J/(kg·K) | Material | , J/(kg·K) |
|---|---|---|---|
| Water (liquid) | 4,186 | Aluminum | about 900 |
| Ice (near 0 °C) | about 2,100 | Concrete | about 880 |
| Steam (near 100 °C) | about 2,000 | Glass | about 840 |
| Ethylene glycol | about 2,400 | Sand, granite | about 800 |
| Ethanol | about 2,440 | Iron, steel | about 450 |
| Human body (average) | about 3,500 | Copper | about 385 |
| Wood | about 1,700 | Brass | about 380 |
| Air (constant pressure) | about 1,005 | Silver | about 235 |
| Olive or vegetable oil | about 2,000 | Mercury | about 140 |
| Paraffin wax | about 2,500 | Lead, gold | about 129 |
Water's specific heat is unusually high because much of the heat goes into stretching and breaking its network of hydrogen bonds rather than into raising molecular speed. That is why coastal climates are mild, why water is used as a coolant and heat store, and why sand on a beach gets far hotter than the sea on the same afternoon. Metals have low specific heats per gram because their atoms are heavy: per mole, most solid elements need about the same (Dulong-Petit), so fewer atoms per gram means less heat per gram.
Worked exampleIdentifying a material from its specific heat
A 190 g sample absorbs 2,052 J and warms by 12.0 °C. J/(g·°C) = 900 J/(kg·K).
That matches aluminum in the table. Specific heat is a fingerprint only when you compare to the values the question supplies.
Worked exampleWhich ends hottest?
The same heat goes into equal masses of copper (385), mercury (140), aluminum (900) and lead (129). , so the largest (aluminum) warms least and the smallest (lead) warms most.
Two objects in contact trade the same amount of heat (energy is conserved); the one with the smaller heat capacity changes temperature more.
Calorimetry measures heat through temperature change. In an insulated mixture, the heat lost by the warm parts equals the heat gained by the cool parts.
Formula #11Energy balance for a mixture
Each term is positive for parts that warm and negative for parts that cool. Add terms for any phase change.
Show worked exampleHide worked example
Worked exampleMixing water
0.200 kg of water at 80.0 °C is mixed with 0.300 kg at 20.0 °C in an insulated cup.
Same , so it cancels: .
, so °C.
Formula #12Final temperature of a two-object mixture (no phase change)
A weighted average of the starting temperatures, weighted by heat capacity. The final temperature always lies between the two starting temperatures and sits closer to the object with the larger .
Show 2 worked examplesHide worked examples
Worked exampleMetal into water
0.150 kg of aluminum () at 95.0 °C goes into 0.0400 kg of water at 10.0 °C.
°C.
Check: the aluminum lost J and the water gained J (equal within rounding).
Worked exampleFinding an unknown specific heat
0.400 kg of metal at 120.0 °C is dropped into 0.450 kg of water at 15.0 °C; the final temperature is 30.0 °C.
Heat gained by water: J. Heat lost by metal: .
J/(kg·K).
If the cup itself has a heat capacity (J/K), add to the "gained" side.
A calorimeter is an insulated container used to measure heat. In a coffee-cup calorimeter (constant pressure, open to the air) the measured heat equals the enthalpy change, . In a bomb calorimeter the reaction happens inside a sealed steel vessel of fixed volume immersed in water, so no expansion work is done and the measured heat equals the change in internal energy, . For a bomb calorimeter with a known total heat capacity , , and the reaction's heat is the negative of that.
Worked exampleHeating with a known power
A heater delivers 67.0 W to 0.114 kg of water. Time to warm it 10.0 °C: s.
With an 85%-efficient 1.2 kW kettle heating 1.5 kg from 10 °C to 100 °C: s.
Efficiency divides the useful heat: input energy = useful heat ÷ efficiency.
Worked exampleMechanical energy into heat
A 4.40 g lead bullet at 250 m/s stops in a target, and all its kinetic energy becomes internal energy of the bullet ( J/(kg·K)).
, so the mass cancels: K.
In the same way a rock falling 15 m into a pail of water converts into heat, and Joule's paddle-wheel experiment converted falling weights into a measurable temperature rise.
Newton's law of cooling
For modest temperature differences, an object's rate of heat loss is roughly proportional to its temperature difference from the surroundings. That makes temperature approach room temperature along an exponential curve, fast at first and then slowly.
Formula #13Newton's law of cooling (or warming)
= time constant in s or min. It is an approximation; radiation-dominated and evaporating systems drift from it.
Many tests write the same law with a cooling constant : , and the rate form "rate of cooling ∝ ".
The key fact is that the difference shrinks by the same fraction in every equal time interval. The constant is always positive (units of 1/time) and is larger for small objects with large surface area, good conductors and moving air. For an object whose inside stays nearly uniform in temperature, convection theory gives it directly: , so a large heat capacity slows cooling and a large speeds it. Because the difference only shrinks by a fraction each interval, the object approaches room temperature ever more slowly and, in this model, reaches it only after infinite time; in practice, after about the remaining difference is under 1% of the starting one. A negative would make the difference grow, so a cooling object would get hotter than its surroundings on its own, which the second law forbids. Solve for or by taking a natural log: . Logarithms are allowed arithmetic on a calculator; no calculus is needed.
Worked exampleA thermometer carried outdoors
A thermometer reads 20 °C indoors, is carried into 5 °C air, and reads 12 °C after 1.0 min.
Differences: 15 at the start, 7 after 1 min. per min.
When does it read 6 °C (difference 1)? min.
Another minute after the first reading (2.0 min total): difference , so it reads 8.3 °C.
Worked exampleEstimating time of death
A body is found at 85.6 °F in a 68.0 °F room; an hour later it reads 82.8 °F. Assume it started at 98.6 °F.
Differences: 17.6, then 14.8 after 1 h, so per hour.
Time since death at the first reading: h before it was measured.
Worked exampleThe quick "average temperature" method
A liquid cools from 65 °C to 55 °C in 5.0 min in a 35 °C room. How long from 45 °C to 37 °C?
Approximate the rate by the average difference: first interval, rate = 10/5.0 = 2.0 °C/min at an average excess of 25 °C, so the constant is per min.
Second interval: average temperature 41 °C, excess 6 °C, rate °C/min, so min.
The exponential form is more exact; use the method the question's wording implies.
The idea matters for Part II in reverse: as your cup warms above room temperature it starts losing heat faster, so the temperature rise per minute shrinks over the Heating Time. A device that keeps losses low holds its warming rate up for longer.
Processes, cycles, engines and the laws
Key factsProcesses and engines in one minute
- First law: ( by the gas); P-V area = work; a cycle has .
- Isothermal ; adiabatic ; isobaric ; isochoric .
- Any engine: . Carnot limit: in kelvin.
- Refrigerator ; heat pump ; both can exceed 1.
- Second law: heat flows hot → cold by itself; no cyclic engine turns all heat into work; total entropy never decreases.
The first law
The first law is energy conservation with heat included: energy cannot be created or destroyed, only transferred or converted. The change in a system's internal energy equals the heat added to it minus the work it does on its surroundings.
Formula #14First law of thermodynamics
= heat added to the system (J), = work done by the system (J). Some books (most chemistry texts) write with done on the system; read the convention in each question.
| Event | Sign of | Sign of (by the system) | Effect on |
|---|---|---|---|
| Heat flows into the system | + | 0 | Raises |
| Heat flows out | − | 0 | Lowers |
| Gas expands, pushing on surroundings | 0 | + | Lowers |
| Gas is compressed (work done on it) | 0 | − | Raises |
For a gas at constant pressure, work done by the gas is (Pa × m³ = J; or L·atm × 101.3 = J). On a pressure-volume (P-V) graph, the work is the area under the process curve: positive when the volume grows, negative when it shrinks, zero for a vertical (constant-volume) line.
Worked exampleA gas in a piston
A gas absorbs 500 J of heat and expands at a constant 100 kPa from 2.0 L to 4.0 L.
J.
J. The internal energy rose, so the gas warmed.
Worked exampleReading the signs
175 J of heat enters a gas while it does 350 J of work: J; the gas cools even though it was heated.
A gas absorbs 500 J, has 240 J of work done on it, then does 125 J of work: J.
96 J of work compresses a gas adiabatically: , so J. An adiabatic expansion doing 12 J of work gives J.
In an isothermal process 500 J of heat is added: , so the gas does 500 J of work.
To leave unchanged you can remove heat while the surroundings do an equal amount of work on the system (or add heat while the system does equal work).
The first law forbids a perpetual motion machine of the first kind, one that puts out more energy than it takes in. An engine claimed to deliver 10 hp (7,460 W) from 6,000 W of input violates the first law; an engine that delivers work with no heat input at all does too.
The four standard processes
| Process | Held constant | First-law consequence | Ideal gas relation | P-V diagram shape |
|---|---|---|---|---|
| Isothermal | Temperature | , so | = constant (Boyle) | Hyperbola |
| Adiabatic | No heat exchange () | : expansion cools, compression warms | = constant (reversible) | Curve steeper than an isotherm |
| Isobaric | Pressure | = constant (Charles) | Horizontal line | |
| Isochoric (isovolumetric, isometric) | Volume | , so | = constant (Gay-Lussac) | Vertical line |
Here , about 1.67 for a monatomic gas and 1.40 for a diatomic gas such as air. On a P-V diagram an adiabat through a point is steeper than the isotherm through the same point. A bicycle pump warming as you pump and a spray can cooling as it empties are both close to adiabatic, because the change is too fast for much heat to flow. Other "iso" names: isenthalpic (constant enthalpy, as in throttling) and isentropic (constant entropy, which is a reversible adiabatic process).
Common pitfallAdiabatic is not isothermal
Adiabatic means no heat flow, and the temperature usually changes. Isothermal means constant temperature, and heat must flow to keep it that way. A truly isothermal compression must be done slowly so heat can leak out as fast as work goes in; a fast compression is closer to adiabatic.
Formula #15Work and heat for an ideal gas in each process
Isothermal:
Isobaric: , , .
Isochoric: , .
Reversible adiabatic: , and are constant; .
is the natural log; in K; for a monatomic gas , so .
Show 3 worked examplesHide worked examples
Worked exampleIsothermal expansion
2.00 mol of ideal gas expands reversibly at 273 K from 19.8 L to 47.3 L.
J (about 3.95 kJ). , so J of heat flows in.
From pressures: 0.50 mol at 298 K expanding from 1.00 atm to 0.25 atm does J.
Worked exampleIsobaric expansion of a diatomic gas
2.0 mol of N₂ at 300 K and 50.0 L doubles its volume at constant pressure, so doubles to 600 K.
J. J. J (or ).
Most of the heat raises internal energy; the rest pushes back the surroundings.
Worked exampleAdiabatic compression (why diesels need no spark)
Air () at 300 K is compressed adiabatically to one-fifteenth of its volume.
K, about 613 °C, above the autoignition temperature of diesel fuel.
Pressure: , not just , because the gas also got hotter.
Key factsSame expansion, different processes
Starting from the same state and expanding to twice the volume, the work done by an ideal gas ranks isobaric > isothermal > adiabatic (, and, for a monatomic gas, ). The adiabatic expansion ends at the lowest pressure and the lowest temperature, because no heat comes in to replace the energy spent as work. For compressions to half the volume the order of work done on the gas reverses (adiabatic > isothermal > isobaric: , and ), and the adiabatic compression ends hottest.
Worked exampleEfficiency of a rectangular P-V cycle
A monatomic ideal gas runs clockwise around a rectangle: A (1.0 L, 300 kPa) → B (3.0 L, 300 kPa) → C (3.0 L, 100 kPa) → D (1.0 L, 100 kPa) → A.
Net work = enclosed area J.
Which legs take in heat? Use . D→A (constant volume, pressure rising): J in. A→B (constant pressure, expanding): J in. B→C and C→D release heat.
.
Check against Carnot: , so , and a Carnot engine between those extremes would reach . Real cycles that add heat over a range of temperatures fall well short.
Reversible, irreversible and quasi-static processes
A quasi-static process happens so slowly that the system passes through a continuous series of equilibrium states; only such a process can be drawn as a line on a P-V diagram. A reversible process is quasi-static and free of dissipation, so it could be run backwards with both the system and the surroundings returned exactly to where they started. It is an ideal limit: the total entropy of system plus surroundings stays constant.
Every real process is irreversible to some degree, and increases total entropy. The usual sources of irreversibility (textbooks group them as mechanical, thermal and chemical) are:
- friction and other dissipation (stirring, electrical resistance),
- heat flowing across a finite temperature difference,
- unrestrained (free) expansion of a gas,
- mixing of different substances, and chemical reactions,
- inelastic deformation.
Two named irreversible processes appear on tests:
- Free (Joule) expansion: a gas rushes into a vacuum inside an insulated container. and (nothing is pushed), so and an ideal gas's temperature is unchanged, but its entropy rises by . It is adiabatic but not isentropic.
- Throttling (Joule-Thomson expansion): a gas is forced through a valve or porous plug from high to low pressure with no heat exchange. Enthalpy is constant (isenthalpic). An ideal gas's temperature does not change, but most real gases at room temperature cool; this cooling drives refrigerator expansion valves and the liquefaction of gases (hydrogen and helium warm instead unless they are first cooled below their inversion temperatures).
Key factsReading a P-V diagram
- Moving right (expansion): the gas does positive work equal to the area under the path. Moving left: work is done on the gas.
- Between the same two states, a path that runs at higher pressure does more work (for an expansion), so it needs more heat; is identical for every path.
- Along an isotherm is constant; isotherms further from the origin (up and to the right) are hotter, because .
- A closed loop is a cycle: net work = enclosed area. Clockwise = heat engine (net work out); counterclockwise = refrigerator or heat pump (net work in).
Cycles and heat engines
A thermodynamic cycle returns a system to its starting state, so over the whole loop and the net work equals the net heat. A heat engine runs a cycle that takes heat from a hot reservoir, does work , and rejects to a cold reservoir.
Formula #16Efficiency of any heat engine
is a fraction (report as a percentage); energies in J or powers in W.
The Carnot cycle is the ideal reversible cycle: isothermal expansion at (absorbing heat), adiabatic expansion down to , isothermal compression at (rejecting heat), and adiabatic compression back to . No engine between the same two reservoirs can beat it.
Formula #17Carnot efficiency
Both temperatures in kelvin. Reaching 100% would need K.
Worked exampleCarnot limit between boiling and freezing water
K, K.
, or 26.8%.
Worked exampleWork from heat input
A Carnot engine takes in 2,000 J between 700 K and 280 K.
, so J and J.
Worked exampleAn ocean thermal engine
Surface water at 20 °C and deep water at 4 °C: K, K.
, about 5.5%. Small temperature differences make poor engines.
The Carnot result has consequences tests love. Efficiency depends only on the two reservoir temperatures, not on the working substance (air, steam, helium) or the engine's design. It rises if goes up or goes down, and lowering by some amount helps more than raising by the same amount (between 373 K and 273 K, a 10 K change gains 2.7 percentage points by lowering but only 1.9 by raising ). A claimed engine that beats is impossible: one said to take 100 J from boiling water, reject heat to a 10 °C room and deliver 80 J of work claims 80% when the limit is . Real engines fall well short of the limit because of friction, heat leaks and finite-speed (irreversible) heat transfer: car engines run at roughly 20–30% (diesels up to about 40%), and large power plants at about 33–45% (combined-cycle plants up to about 60%).
Worked exampleHeat flows in a power-limited engine
A 550 W Carnot engine runs between 125 °C (398 K) and 50 °C (323 K). .
Heat taken in per second: W. Heat exhausted: W.
Low efficiency means most of the input leaves as waste heat.
Worked exampleEfficiency from heat flows only
A furnace supplies 80 MW and the plant rejects 50 MW to a river. (37.5%), and the electrical output is 30 MW.
An engine at its maximum possible efficiency that takes in 80 J and rejects 20 J does 60 J of work (75%), so its reservoirs must satisfy .
Named cycles
Real engines follow other cycles, and tests show their P-V diagrams. Recognize each by its shape: vertical segments are isochoric, horizontal segments are isobaric, and the steep curves are adiabats (isentropic in the ideal cycle). The Carnot cycle is the only one built from isotherms and adiabats alone; it is impractical because truly isothermal steps must run infinitely slowly.
| Cycle | Steps (ideal) | Where it is used |
|---|---|---|
| Carnot | Isothermal expansion, adiabatic expansion, isothermal compression, adiabatic compression | Theoretical upper limit only |
| Otto | Adiabatic compression, isochoric heat addition (spark), adiabatic expansion (power), isochoric heat rejection | Gasoline (spark-ignition) engines |
| Diesel | Adiabatic compression, isobaric heat addition, adiabatic expansion, isochoric heat rejection | Diesel (compression-ignition) engines; no spark plug |
| Brayton (Joule) | Adiabatic compression, isobaric heat addition, adiabatic expansion, isobaric heat rejection | Gas turbines and jet engines |
| Stirling | Isothermal compression, isochoric heating, isothermal expansion, isochoric cooling (with a regenerator) | External-combustion engines; can approach Carnot efficiency |
| Rankine | Pump compresses liquid, boiler adds heat at constant pressure, turbine expands steam adiabatically, condenser rejects heat at constant pressure | Steam power plants (coal, nuclear, solar thermal); boiling and condensing also happen at constant temperature; variants run on low-temperature heat sources too (organic Rankine) |
| Vapor-compression refrigeration | Compressor, condenser, expansion (throttling) valve, evaporator | Refrigerators, air conditioners, heat pumps |
A four-stroke engine runs intake, compression, power and exhaust strokes, two crankshaft turns per cycle. The ideal Otto efficiency depends only on the compression ratio :
Formula #18Otto cycle efficiency
= compression ratio (no units), for air. Example: gives ; gives 60.2%. Real gasoline engines get about half of that.
Diesel engines use higher compression ratios (about 14 to 23) because they compress only air, which cannot knock; the high ratio is what makes them more efficient than gasoline engines. At the same compression ratio, though, the ideal Otto cycle is the more efficient of the two; diesels come out ahead only because they can use much higher ratios.
On a temperature-entropy (T-S) diagram (Division C, State & National) the Carnot cycle is a rectangle: two horizontal isotherms and two vertical adiabats (constant entropy). The heat absorbed is , the heat rejected is , and the enclosed area is the net work, which gives at a glance.
Refrigerators, air conditioners and heat pumps
Refrigerators and heat pumps are heat engines run in reverse: work moves heat out of a cold space and dumps into a warm one. The cold space is the cold reservoir; the room (or the outdoors, for an air conditioner) is the hot reservoir. An air conditioner is a refrigerator for a house; a heat pump is the same machine used to heat the warm side.
The working fluid, the refrigerant, carries heat around a loop:
- Compressor (driven by the work input): squeezes low-pressure vapor into hot, high-pressure vapor.
- Condenser (coils on the back or outside): the hot vapor gives off heat to the room and condenses to a liquid.
- Expansion valve (throttling): the liquid's pressure drops suddenly, and part of it flashes to vapor, cooling it far below the cold-space temperature.
- Evaporator (coils inside the cold space): the cold refrigerant absorbs heat and evaporates, then returns to the compressor.
Formula #19Coefficient of performance
Temperatures in kelvin. Unlike efficiency, a COP is usually greater than 1: moving heat costs less work than the heat moved.
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Worked exampleRefrigerator numbers
A refrigerator removes heat from its interior at 540 W with a COP of 3.0. Power input: W. Heat dumped into the kitchen: W.
Carnot limit for a 2.0 °C interior in a 24.0 °C room: .
Heat rejected by a fridge that uses 300 J of work to remove 150 J: J.
A refrigerator removing 360 kJ/min with a 2 kW (120 kJ/min) input rejects kJ/min to the kitchen.
Worked exampleHeat pump on a cold night
Heating a room at 20 °C (293 K) from outdoor air at 0 °C (273 K): Carnot .
On Mars at −63 °C (210 K): . The bigger the temperature gap, the worse a heat pump performs.
Home heat pumps are classed by where they get their heat: air-source heat pumps (the most common; they draw heat from outdoor air), ground-source or geothermal heat pumps (pipes buried in the ground, where the temperature stays nearly constant year-round, giving a higher COP in winter), and water-source heat pumps (a well, lake or water loop). Running the same machine backwards in summer makes it an air conditioner.
Leaving a refrigerator door open to cool a kitchen makes the kitchen warmer: the fridge dumps into the same room it takes from.
The second law
The second law has two classic statements that are logically equivalent:
- Clausius statement: heat does not flow on its own from a colder body to a hotter one. A refrigerator needs work input.
- Kelvin-Planck statement: no cyclic engine can take heat from a single reservoir and turn all of it into work. Every engine must reject some heat.
Together they explain why the Carnot limit exists and why real processes run one way. If either statement could be broken, a device could be built that breaks the other. In entropy language (Division C at State and National goes further below): the total entropy of an isolated system never decreases, and it increases in every irreversible process; an isolated system settles into equilibrium, the state of maximum entropy.
A spontaneous process is one that happens on its own once started, without continuing outside work: heat flowing from hot to cold, a gas spreading into a vacuum, ice melting in a warm room, iron rusting. The reverse processes are nonspontaneous; they can be made to happen only by doing work (a refrigerator, a pump). "Spontaneous" says nothing about speed: diamond turning to graphite is spontaneous but immeasurably slow. A spontaneous process always increases the entropy of the universe (system plus surroundings), even if the system's own entropy falls, as when water freezes below 0 °C and releases heat that raises the surroundings' entropy more.
A perpetual motion machine of the second kind would run in a cycle and turn heat from a single reservoir entirely into work (for example, a ship powered by cooling the ocean). It would not violate energy conservation, but it violates the second law. Isothermal expansion of an ideal gas turns all the absorbed heat into work in one step, which is allowed: it is not a cycle, and the gas ends up at a larger volume.
Other ideas tied to the second law: the arrow of time (we see eggs break but never unbreak); heat death of the universe, the far-future state in which everything reaches one temperature and no work can be extracted; and Maxwell's demon (see History), a thought experiment that seemed to break the second law until it was shown that the demon's information handling (above all, erasing its memory) generates at least as much entropy as its sorting removes. Biology does not escape the law: a steer must eat far more grain than the muscle it builds, because each conversion loses energy as heat.
Key factsThe four laws in one place
| Law | Plain statement | Typical examples |
|---|---|---|
| Zeroth | Two bodies each in thermal equilibrium with a third are in equilibrium with each other; temperature is meaningful | Reading or calibrating a thermometer; hot and cold blocks reaching one temperature |
| First | Energy is conserved: | A gas heated in a piston; "no perpetual motion of the first kind"; a cycle has |
| Second | Heat flows hot → cold on its own; no engine is 100% efficient; total entropy increases | Carnot limit, refrigerators need work, melting ice in a warm room, heat death |
| Third | Entropy of a perfect crystal → 0 as → 0 K; 0 K cannot be reached | Absolute zero unattainable; one microstate () for a perfect crystal at 0 K |
A popular mnemonic: you can't win (first law), you can't break even (second), and you can't get out of the game (third). Conservation of mass, Newton's laws and "energy has a tendency to become less disordered" are not laws of thermodynamics.
History of thermodynamics
The 2027 outline names eight scientists. History questions come in three forms: "who did this?" (match a person to a discovery, book or quotation), "what did this person do?" (choose-all-that-apply), and "put these in order" or "which century". Learn each person with two or three contributions, a key year and a phrase that identifies them.
ReferenceThe eight named scientists· 8 rows
No rows match.
| Scientist (lifespan, country) | Key contributions | Key dates | Identifying phrases |
|---|---|---|---|
| Joseph Black (1728–1799, Scotland; born in Bordeaux, France) | Distinguished heat (quantity) from temperature (intensity); discovered latent heat (ice absorbs heat while melting without warming) and introduced specific heat (heat capacity); also identified carbon dioxide ("fixed air") | CO₂ 1750s; latent heat about 1761–62 (taught in Glasgow and Edinburgh lectures, published after his death) | "latent heat", "specific heat", "heat ≠ temperature"; friend and supporter of James Watt |
| Sadi Carnot (Nicolas Léonard Sadi Carnot, 1796–1832, France) | Reflections on the Motive Power of Fire (1824), the first theory of heat engines: the ideal reversible engine (Carnot cycle), maximum efficiency set only by the reservoir temperatures, independent of working substance; first form of the second law; first idea of reversibility | 1824; died of cholera at 36 | "father of thermodynamics", "motive power of fire", "perfect engine"; he still used the caloric (heat-fluid) theory |
| James Prescott Joule (1818–1889, England) | Showed heat and work are equivalent forms of energy: the mechanical equivalent of heat (falling weights turning a paddle wheel in insulated water); Joule's law of electrical heating (); free-expansion experiment; the Joule-Thomson effect with Kelvin; the SI unit of energy is named for him | Electrical heating 1840–41; first announced 1843 (British Association); paddle-wheel experiment 1845, refined value read in 1849 and published in 1850 (about 772 ft·lbf per BTU, about 4.16 J/cal) | Brewer from Salford near Manchester; "mechanical equivalent of heat"; led to conservation of energy (first law); helped overturn caloric theory |
| William Thomson, Lord Kelvin (1824–1907, born Belfast, worked in Glasgow) | Absolute temperature scale based on Carnot's theory (1848), with absolute zero near −273 °C; Kelvin statement of the second law (1851, On the Dynamical Theory of Heat); coined the term "thermodynamic(s)" (1849–1854); Joule-Thomson effect; idea of the dissipation of energy and "heat death"; transatlantic telegraph engineering | 1848, 1851; made Baron Kelvin in 1892 | "absolute zero", "absolute scale", "kelvin unit", defined thermodynamics as the relation of heat to forces between parts of bodies and to electrical agency |
| Rudolf Clausius (1822–1888, Germany) | First clear statement of the second law (1850, On the Moving Force of Heat), reconciling Carnot's engine theory with Joule's conservation of energy; introduced the quantity he later named entropy (1854; named 1865, from the Greek for "transformation"); Clausius statement (heat does not flow cold to hot unaided); kinetic theory, mean free path (1858); virial theorem (1870) | 1850, 1854, 1865 | "entropy", "the energy of the universe is constant; the entropy of the universe tends to a maximum"; old entropy unit the clausius = 1 cal/K |
| James Clerk Maxwell (1831–1879, Scotland) | Distribution of molecular speeds in a gas (1860); kinetic theory; Maxwell's demon thought experiment (1867 letter, published in his book Theory of Heat, 1871); Maxwell relations; also unified electricity and magnetism | 1860, 1867, 1871 | "demon", "speed distribution", Theory of Heat |
| Ludwig Boltzmann (1844–1906, Austria) | Statistical meaning of entropy, (1877); Maxwell-Boltzmann distribution; H-theorem and the Boltzmann equation (1872); derived the Stefan-Boltzmann law from theory (1884) after his teacher Josef Stefan found it experimentally (1879); equipartition | 1872, 1877, 1884 | " is engraved on his tombstone in Vienna"; Boltzmann constant (named and introduced into the formula by Planck) |
| Max Planck (1858–1947, Germany) | Blackbody radiation law (1900), which required energy to come in quanta and introduced Planck's constant ; founded quantum theory; his wording of the second law gives the Kelvin-Planck statement; wrote Boltzmann's entropy formula in its modern form | 1900; Nobel Prize in Physics 1918 | "quanta", "Planck's constant", solved the ultraviolet catastrophe |
How the story fits together, in order:
- 1760s, heat as a substance. Black separated the amount of heat from the temperature, discovering latent and specific heat. Like most scientists of his time he thought of heat as a fluid, later called caloric, that flowed from hot bodies to cold ones and was conserved.
- 1824, engines. Carnot, trying to improve the steam engines that powered industry, asked what limits their efficiency. Using the caloric picture, he showed that the limit depends only on the hot and cold temperatures. His book was little noticed until others revived it.
- 1840s, heat is energy. Joule's careful experiments showed that a fixed amount of work always produces the same amount of heat. Heat is a form of energy, not a substance, which became the first law (conservation of energy). Caloric theory was then abandoned in favor of the mechanical (kinetic) theory of heat.
- 1848–1854, the second law. Kelvin built an absolute temperature scale on Carnot's ideas. Clausius (1850) showed that in an engine heat is not just passed along, as caloric theory said, but partly consumed, in proportion to the work produced, with the rest flowing to the cold body. He and Kelvin (1851) thus reconciled Carnot's result with Joule's: energy is conserved, and heat cannot be turned entirely into work or flow uphill on its own. The first and second laws emerged together in the mid-1800s.
- 1850s–1880s, molecules. Clausius, Maxwell and Boltzmann explained these laws through the motion of molecules: the kinetic theory of gases, the speed distribution, and entropy as a count of microstates.
- 1900 onward. Planck's blackbody law launched quantum physics; the third law (Walther Nernst, 1906–1912) and the zeroth law (named around 1935) completed the set.
Names outside the list still appear in older practice tests as distractors or background; you are not expected to know them in depth for 2027, but recognizing them avoids traps: Josef Stefan (the law, 1879), Walther Nernst (third law), William Rankine (Rankine scale and cycle), Daniel Fahrenheit and Anders Celsius (temperature scales), Benjamin Thompson, Count Rumford (cannon-boring evidence against caloric), Rudolf Diesel and Nikolaus Otto (engines), James Watt, Thomas Newcomen and Thomas Savery (steam engines), and J. Willard Gibbs (free energy, phase rule).
State & National: radiation and the third law
Rules scopeState & National only, both divisions
Everything in this section is outside Regional scope.
Blackbody radiation
A blackbody is an ideal object that absorbs all radiation falling on it and emits the maximum possible thermal radiation at every wavelength for its temperature. Its spectrum depends only on temperature. As temperature rises, the curve grows taller everywhere and its peak shifts to shorter wavelengths: a stove element glows dull red, a hotter filament glows yellow-white. Planck's 1900 formula describes this curve, and it only works if energy is exchanged in discrete quanta.
Classical physics (the Rayleigh-Jeans law) predicted that a blackbody should emit ever more energy at ever shorter wavelengths, an infinite total: the ultraviolet catastrophe. Planck fixed it in 1900 by assuming that an oscillator of frequency can only gain or lose energy in whole packets, ( J·s). At short wavelengths these packets are so large that thermal energy (about ) rarely supplies one, so emission falls off, matching experiment. That assumption was the start of quantum theory.
Key properties of blackbody radiation: the spectrum is continuous; it depends only on temperature, not on the material or shape; a blackbody is both the best possible absorber and the best possible emitter at every wavelength; and a small hole in a hollow box (a cavity) is the best real approximation. Stars, glowing metal and incandescent filaments are close to blackbodies. The most nearly perfect blackbody spectrum ever measured is the cosmic microwave background, the leftover radiation of the early universe, at 2.725 K (peak near 1 mm, in the microwave band). Real objects that emit a fixed fraction of the blackbody amount at every wavelength are called gray bodies.
Formula #20Wien's displacement law
in m, in K.
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Worked examplePeak wavelengths
The Sun's surface, about 5,800 K: m (500 nm, visible).
A filament assumed to be 2,500 K: m (about 1.2 μm, near infrared). This is why an incandescent heat lamp puts out most of its energy as infrared rather than light.
A person at 310 K: m (long-wave, thermal infrared).
Inverted: a star whose spectrum peaks at 550 nm has K. Earth at 288 K peaks near 10 μm, in the thermal infrared.
Color tracks temperature: as an object heats it glows dull red (about 800 K), then orange, yellow and white; the hottest stars look blue-white. A body's color and peak wavelength tell you its temperature; its total output tells you its temperature and size.
Radiant exitance and the Stefan-Boltzmann law
Radiant exitance is the radiant power emitted per unit area of a surface, in W/m². For a blackbody it depends only on temperature, through the Stefan-Boltzmann law. Real surfaces emit a fraction (the emissivity, from 0 to 1) of the blackbody value.
| Radiometric quantity | Meaning | Units |
|---|---|---|
| Radiant energy | Total energy carried by radiation | J |
| Radiant flux (radiant power) or | Energy per second, emitted, transferred or received | W |
| Radiant exitance | Power emitted per unit area of a source surface | W/m² |
| Irradiance | Power received per unit area of a surface (sunlight on a panel) | W/m² |
| Radiant intensity | Power per unit solid angle from a source | W/sr |
| Radiance | Power per unit area per unit solid angle | W/(m²·sr) |
Exitance and irradiance share units but point in opposite directions: exitance leaves a surface, irradiance arrives at one. The solar constant is an irradiance.
Formula #21Stefan-Boltzmann law
W/(m²·K⁴), in kelvin, in m², in W/m², in W. Net exchange with surroundings at : .
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Worked exampleRadiant exitance and the fourth power
A blackbody surface at 300 K: W/m².
At 600 K (twice the kelvin temperature): times as much, about 7,350 W/m².
A surface with (polished metal) at 300 K emits only about 46 W/m².
Common pitfallKelvin to the fourth power
Stefan-Boltzmann answers are wildly wrong with Celsius. Doubling a Celsius temperature does not double the absolute temperature, so it does not multiply the output by 16.
Worked exampleRatios with the fourth power
A blackbody warmed from 0 °C to 100 °C: times the exitance.
A plate at 125 °C (398 K) emits 1,500 W/m². To emit twice as much: K, about 200 °C.
If the Sun's surface temperature halved, its output (and the energy reaching Earth) would fall by .
Worked exampleThe Sun's luminosity
Surface 5,778 K, radius m, area m².
W.
Worked exampleNet radiation from a warm object
A sphere of radius 2.00 m ( m²), blackbody, at 47 °C (320 K) in surroundings at 20 °C (293 K):
W.
A person (about 1.8 m², , skin 306 K) in a 293 K room loses roughly 140 W net by radiation; the total each way is far larger, but the two nearly cancel.
Emissivity matters too: a body at 50 °C with and 1.4 m² of area in a 20 °C room loses W.
Luminosity, distance and comparing stars
Total power from a sphere is its luminosity, , so . That power spreads over ever larger spheres, so the irradiance at distance follows the inverse-square law: .
Worked exampleFrom the Sun's luminosity to the solar constant
W/m² at Earth's distance.
At twice the distance the irradiance is a quarter as large. A star with twice the Sun's radius but half its surface temperature has of the Sun's luminosity.
Worked exampleEnergy of one photon
Planck's relation . Green light at 500 nm: J. Shorter wavelength (higher frequency) means more energy per photon; this is why ultraviolet light can cause sunburn and infrared cannot.
Radiative balance and planetary temperature
A planet (or any object in sunlight) settles at the temperature where the radiation it absorbs equals the radiation it emits. Sunlight of intensity (the solar constant, about 1,361 W/m² at Earth) falls on the planet's cross-section, a disk of area . A fraction , the albedo, is reflected (about 0.30 for Earth). The planet emits from its whole surface, .
Formula #22Equilibrium temperature of a planet
The factor 4 is the ratio of the emitting sphere to the intercepting disk. The radius cancels, so planet size does not matter.
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Worked exampleEarth without a greenhouse effect
K (−18 °C).
The real average surface temperature is about 288 K (15 °C); the 33 K difference is the greenhouse effect.
With albedo 0.70 (an icy "snowball" Earth): K. Higher albedo means less absorbed sunlight and a colder planet. (Kirchhoff's law links absorption and emission at the same wavelength: snow reflects visible sunlight yet emits infrared almost like a blackbody, which is why is kept here.)
If a surface absorbs a flux from all around and re-emits it, : 1,000 W/m² gives K. Because the absorbed sunlight falls as and , a planet's equilibrium temperature scales as : with Earth's albedo, a planet at Mars's distance (1.52 AU) would sit at K.
The third law
The third law says that the entropy of a perfect crystal of a pure substance approaches a constant, taken as zero, as its temperature approaches absolute zero. In Boltzmann's terms, a perfect crystal at 0 K has exactly one possible arrangement, , so . That gives entropy an absolute zero point, which is why tables list absolute ("standard molar") entropies rather than just changes, and why every substance above 0 K has a positive .
A practical consequence is that absolute zero cannot be reached in a finite number of steps: each cooling step removes a smaller and smaller amount of entropy, so the approach is endless (laboratories have reached billionths of a kelvin, never zero). A Carnot engine would reach 100% efficiency only with a 0 K cold reservoir, and the third law says that reservoir cannot exist; but the law that forbids a 100%-efficient engine is the second law (Kelvin-Planck). The law grew out of Walther Nernst's heat theorem (1906–1912) and is stated in Planck's form as "S → 0 for a perfect crystal".
Real crystals often keep some residual entropy near 0 K because their molecules are frozen into slightly disordered arrangements (carbon monoxide molecules pointing CO or OC at random, the hydrogen positions in ice). Glasses and other non-crystalline solids are not covered by the "S = 0" statement. In Division B at State and National, expect the statement and its consequences rather than entropy calculations.
Division C, State & National: entropy and enthalpy
Rules scopeDivision C State & National only
Division B does not test this section at any level.
Entropy
Entropy is a state function that measures how spread out energy is, or statistically, how many microscopic arrangements (microstates, ) fit a given macroscopic state. It is often described as "disorder", which is a useful shorthand but not a definition. The second law in entropy language: the total entropy of an isolated system never decreases, and it increases in any irreversible process; it stays constant only in an idealized reversible process. Entropy is extensive, measured in J/K (or J/(mol·K) per mole).
Formula #23Entropy change at constant temperature
in J/K, in J (positive into the system), in K.
In , (often written ) is the number of microstates, not work.
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Worked exampleMelting and boiling
Melting 1.00 kg of ice at 273.15 K: J/K.
Boiling 0.100 kg of water at 373.15 K: J/K.
Both are positive: liquid has more microstates than solid, and vapor far more than liquid.
Worked exampleHeat flowing between two reservoirs
1,000 J flows from a reservoir at 400 K to one at 300 K.
Hot side: J/K. Cold side: J/K.
Total: J/K. The positive total is the second law: heat flowing hot to cold always increases total entropy.
Because the rules exclude calculus, expect entropy questions at fixed temperature (phase changes, reservoirs), sign reasoning (does entropy rise or fall?), and the statistical picture. Formulas for changing temperature or volume are given as results to apply:
Formula #24Entropy changes you can compute without calculus
Warming or cooling (no phase change):
Ideal gas at constant temperature (isothermal, or a free expansion between the same states):
Reversible adiabatic (isentropic): . Any complete cycle: (state function).
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Worked exampleWarming water and mixing gases
1.00 kg of water warmed from 20 °C to 80 °C: J/K.
Two equal chambers, one holding 1.00 mol of ideal gas and one empty; the partition is removed: J/K, although . Two different gases, 1 mol each, mixing into the doubled volume: each gains , total 11.5 J/K.
Worked exampleA Carnot engine's entropy budget
A reversible engine takes 300 kJ from 600 K and rejects heat to 300 K. It rejects kJ.
Hot reservoir: kJ/K. Cold reservoir: kJ/K. Engine (a cycle): 0. Total: 0, the mark of a reversible process.
A real engine rejecting 200 kJ instead: cold reservoir kJ/K, total kJ/K, positive as the second law demands.
Worked exampleCounting microstates
Four coins: there are equally likely arrangements. "2 heads, 2 tails" can happen 6 ways, "4 heads" only 1, so the mixed macrostate is the most probable: it has the most microstates and the highest entropy.
Let gas molecules double their volume: each now has twice as many positions, so grows by and . For one mole () that is J/K, the same answer as the free-expansion formula.
Worked exampleEntropy of mixing hot and cold water
1.00 kg at 80 °C mixes with 1.00 kg at 20 °C; both end at 50 °C (323.15 K).
Hot water: J/K. Cold water: J/K.
Total: J/K. The cold water gains more entropy than the hot water loses, because the same heat counts for more at a lower temperature.
Worked exampleIce melting in a warm room
1.00 kg of ice at 0 °C melts using heat from a room at 20 °C (ignore the meltwater warming).
Ice: J/K. Room: J/K. Universe: J/K, so the process is spontaneous. In a −10 °C room the signs flip and the ice cannot melt.
Predicting the sign of ΔS. Entropy increases when:
- a solid melts, a liquid vaporizes, or a solid sublimes ();
- a reaction produces more moles of gas than it consumes (for example );
- a molecule breaks into smaller pieces, a solid dissolves, or two gases or liquids mix;
- a gas expands into a larger volume, or any substance is heated;
- larger and more complex molecules, and planets with atmospheres, have more ways to store energy and higher entropy.
It decreases for the reverse: freezing, condensing, deposition, fewer gas moles (for example ), crystallizing from solution. Count moles of gas first, because gas dominates entropy. When the gas moles are equal on both sides the gas term roughly cancels and the other phases decide: burning solid glucose, , has 6 mol of gas in and 12 out, so ; with liquid water as the product (6 in, 6 out) the solid breaking into many small molecules still makes positive (about +260 J/K per mole of glucose from standard-entropy tables). A system's entropy can fall, as when water freezes or sugar crystallizes as its solution evaporates, but only if the surroundings gain more, so for every spontaneous process. At constant temperature and pressure, , so an exothermic process raises the surroundings' entropy.
Standard molar entropies are absolute values (thanks to the third law), so reaction entropies come from a table the same way reaction enthalpies do:
Formula #25Standard reaction entropy
in J/(mol·K). Unlike , the of an element in its standard state is not zero.
Show worked exampleHide worked example
Worked exampleMaking ammonia
, with = 191.6, 130.7 and 192.5 J/(mol·K).
J/K: four moles of gas become two, so entropy falls.
With kJ at 298 K: J/K, so J/K and the reaction is spontaneous at room temperature. At high temperature shrinks and the balance tips the other way.
At a phase change in equilibrium, , so the transition temperature is . Example: ethanol has kJ/mol and J/(mol·K), so it boils at K = 78.4 °C.
NoteFree energy is outside the 2027 outline
Chemistry courses combine these ideas in the Gibbs free energy, (negative for a spontaneous process at constant and ). The 2027 outline names only entropy and enthalpy, so expect spontaneity questions phrased through ; the sign logic is the same: with is spontaneous at every temperature, with never is.
Enthalpy
Enthalpy is defined as : the internal energy plus the energy needed to make room for the system at its pressure. It is an extensive state function, measured in joules. At constant pressure, the heat absorbed equals the enthalpy change, , which is why heats of reaction, fusion and vaporization are tabulated as enthalpy changes. A negative is exothermic (heat released to the surroundings, which warm); a positive is endothermic (heat absorbed from the surroundings, which cool). Enthalpy is a state function, so Hess's law lets you add the values of steps to get the overall change. The name is usually credited to Heike Kamerlingh Onnes (around 1909) and came into wide use in the 1920s.
Worked exampleEnthalpy versus internal energy on boiling
Boiling 1.00 mol (0.018 kg) of water at 373 K and 1 atm takes kJ.
The vapor pushes back the atmosphere: kJ (liquid volume neglected).
So kJ. Most of the energy goes into separating molecules; a small share does work on the air.
For reactions involving gases, the same idea gives , where is moles of gaseous products minus gaseous reactants. When the moles of gas fall (as in , ), is larger (less negative) than . For melting and freezing the volume barely changes, so .
Worked exampleΔU from ΔH
, kJ at 298 K. Gas moles: .
kJ.
Standard enthalpy of formation, , is the enthalpy change to form one mole of a compound from its elements in their standard states (the stable form at 1 bar, usually 25 °C). By definition for an element in its standard state, such as O₂(g), N₂(g), C(graphite) or Br₂(l), but not for H(g) atoms, O₃ or diamond.
Formula #26Reaction enthalpy from formation enthalpies
= coefficients from the balanced equation. Bond-enthalpy estimate: . Breaking bonds absorbs energy; forming bonds releases it.
Show 2 worked examplesHide worked examples
Worked exampleCombustion of methane by Hess's law
with : CH₄ −74.8, CO₂ −393.5, H₂O(l) −285.8 kJ/mol; O₂ 0.
kJ/mol.
Exothermic: the products sit lower in energy than the reactants.
Worked exampleHeat of combustion from a calorimeter
Burning 1.00 g of ethanol (0.0217 mol) warms 235 g of water by 30.0 °C: kJ.
kJ/mol (the table value is −1,367 kJ/mol). The sign is negative because the reaction released the heat the water gained.
Scaling: a thermochemical equation is extensive. If burning 1 mol of propane (44.1 g) releases 2,220 kJ, burning 25.0 g releases kJ. Reversing a reaction flips the sign of .
Endothermic examples: melting, boiling, sublimation (dry ice: positive ), dissolving ammonium nitrate (cold packs), photosynthesis. Exothermic examples: combustion, freezing, condensation, neutralization, dissolving magnesium sulfate or calcium chloride (the solution warms), hand warmers (iron oxidizing). In an endothermic reaction the products have higher potential energy than the reactants; in an exothermic one, lower. An exothermic process need not release its energy only as heat: a burning candle also gives off light, a battery's reaction delivers electrical work, and an explosion releases sound and mechanical work.
Internal energy, enthalpy and entropy are all state functions; heat and work are not, because their values depend on the path between two states.
The heat-collecting device (Part II)
What the device must do
Your device collects energy from a supervisor's heat lamp and delivers it to 100 mL of room-temperature water in a clear 9 oz plastic party cup. The rules treat this as a heating problem, not an insulation problem: you are scored on how much the water warms and on how well you predict its final temperature.
Construction limits
- Materials. Almost anything is allowed. The exceptions are hazardous materials such as asbestos, mineral wool and fiberglass; thermometers and probes; and commercially made thermoses, coolers or vacuum-sealed containers. A device with a hazardous material may not be set up or tested at all, and the team takes only the written test.
- No energy sources. No electrical parts, battery heaters, chemical reactions or similar. A device found to use one scores zero for both TS and PS, and the supervisor may ask you to take the device apart after testing to check.
- Size. With the cup of water in place, the whole setup must fit inside a 30.0 cm cube.
- The cup. You must be able to put the supervisor's cup into the device and take it out. Device parts may reach inside the cup, but nothing may touch the water and nothing may be added to it.
- Temperature. No part may be noticeably warmer or colder than the room at the start, so pre-heated or chilled parts are out.
- Questions. Be ready to explain how the device was designed, built and operates.
The test setup
The supervisor uses a clamp lamp with a metal reflector and a 100-125 W heat-lamp bulb that is not tinted and not an LED, halogen or ceramic bulb, hung pointing down over the table. Your device sits centered beneath it, and the lamp stand's feet stay at least 15 cm from the bulb's center. The bulb height and Heating Time are the same for every team in a tournament but change between tournaments:
| Level | Bulb height (lowest point of bulb above the table) | Heating Time |
|---|---|---|
| Regional | 40-50 cm, in 5 cm steps | 10 min |
| State | 40-55 cm, in 5 cm steps | 10-15 min, in 1 min steps |
| National | 40-65 cm, in 1 cm steps | 10-15 min, in 1 min steps |
Because the device may be at most 30 cm tall, there is always at least 10 cm between the top of a 30 cm device and the bottom of the bulb.
The testing sequence
- The supervisor announces bulb height, Heating Time, room temperature, water-bath temperature and the bulb's specifications (wattage and dimensions).
- Device Setup Time, 3 minutes. Set up or adjust the device, fix any construction problems, and start your prediction. The clock keeps running through any re-checks, and after this only inserting or removing the cup is allowed.
- The supervisor pours 100 mL from the bath into your cup, measures its starting temperature to 0.1 °C, and tells you.
- Water Setup Time, up to 1 minute. Put the cup in the device without otherwise handling the cup or water.
- The lamp turns on and the Heating Time starts. Touching the device or the lamp setup during heating zeroes both TS and PS.
- Lock in your prediction, in °C, before the Heating Time ends.
- When the lamp goes off, lift the cup fully out and set it on the table apart from the device; the supervisor reads the final temperature to 0.1 °C, aiming to finish within a minute.
- Review your recorded data with the supervisor before leaving. If you plan to appeal anything about Part II, leave your device in the competition area.
The physics of a good collector
Start with an energy budget. Warming 100 mL of water by needs joules.
Worked exampleWhat a few watts buys
Suppose the device delivers an average of 5.0 W into the water for a 10-minute Heating Time.
Energy: J.
Rise: °C.
The same 5.0 W for 15 minutes gives about 10.7 °C, before losses grow. This is an illustration, not a typical score; measure your own device.
Most of the lamp's 100-125 W never reaches the cup. A heat lamp radiates over a wide cone, much of it misses the cup's small mouth (about 7.5 cm across), and some of what arrives is reflected or warms device parts instead of water. A good design works on four levers:
- Capture more radiation. Reflective surfaces (for example aluminum foil on a cone or funnel) can redirect rays that would miss the cup back toward it. The wider the opening that catches light within the 30 cm limit, the more power is intercepted.
- Absorb it where it counts. Water absorbs infrared strongly, and the clear cup lets much radiation through to it. Dark, matte surfaces absorb well; a dark sleeve hugging the outside of the cup turns radiation into heat right at the cup wall. Keep absorbers thin and light: every part that warms stores energy that never reaches the water ( again).
- Stop the heat from leaving. Warm air above the water rises away by convection; a clear cover that transmits the lamp's radiation but blocks air flow traps it (the greenhouse idea). Foam under and around the lower cup cuts conduction into the table.
- Get closer, carefully. Radiation spreads out with distance, so intensity falls roughly with the square of the distance from a small source. A lamp in a reflector is not a point source, so treat the inverse-square law as a rough guide and calibrate. Plastics and paper near a 125 W bulb can soften or scorch; build with heat-tolerant materials near the top and never aim a lens or mirror's focus onto the plastic cup.
Common pitfallInsulation alone is not enough
A thick insulating box that blocks the lamp keeps the water at room temperature. The device must let radiation in and then keep the resulting heat in the water.
Calibrating your prediction
The Prediction Score rewards a careful testing log more than a clever design. Build the lamp setup at home with the same bulb types and a 9 oz clear cup, then:
- Run every combination you might face: heights 40, 45, 50 and 55 cm for Regionals and States (and finer steps up to 65 cm for Nationals), and Heating Times of 10 to 15 minutes.
- Record room temperature, starting water temperature, height, time, bulb wattage and final temperature for each run. Repeat each condition at least three times and note the spread.
- Plot temperature gain against height for each Heating Time, and against time for each height. Bring these graphs and tables to the event; the rules allow them.
- Note how the gain changes when the starting water is cooler or warmer than the room. Water that starts below room temperature also gains heat from the air.
During the event, find the announced height and time in your table, adjust for the announced wattage and start temperature, and write final = start + expected gain.
TipSame device, same habits
Practice the full sequence with a timer: 3 minutes of setup, a 1-minute cup insertion, hands off during heating, and a fast cup removal. A cup that sticks in the device costs degrees while it cools.
Scoring
All scoring uses °C, and the highest final score wins.
Formula #27Part scores
Show worked exampleHide worked example
Worked exampleA full score
Your team scores 62 on the test; the best test score is 80. .
Start 21.4 °C, final 29.8 °C: °C. The best TG is 12.0 °C. .
You predicted 28.6 °C: . The best PE is 0.9968. .
.
Penalties and special cases:
| Situation | Effect |
|---|---|
| Each competition-rule violation | TS and PS × 0.9 |
| Each construction violation still present when Setup Time ends | TS and PS × 0.7 |
| Energy source in the device | TS = 0 and PS = 0 |
| Touching the device or lamp setup during heating | TS = 0 and PS = 0 |
| No prediction before heating ends | PS = 0 |
| No device, or not allowed to test for safety reasons | TS = 0 and PS = 0; the written test still counts |
| Hazardous material in the device | Device not tested; written test only |
Ties are broken by best TS, then best Exam Score, then preselected test questions.
Worked exampleThe cost of one construction violation
With one unfixed construction violation, the team above keeps ES = 38.75 but gets and .
: about 12 points lost. Fix problems during Setup Time.
Two features of the formulas shape strategy. First, PE divides your miss by the final temperature in °C, so with water near 30 °C a 1 °C miss costs only about 3% of PE; most teams' PE values are close together, and the gap between teams comes mostly from TS and ES. Second, TS is relative to the best device in the room, so a strong collector that heats the water a few degrees more than the field earns a large share of the 30 points.
Strategy
Splitting the work
Decide roles before the tournament. One partner owns the device: setup, cup insertion and removal, and the prediction from the calibration tables. The other starts the written test immediately and keeps going. If the supervisor allows test work during the Heating Time, both of you can return to the test once the prediction is locked in. On the test, one partner can take calculations (gas laws, engines, calorimetry, Stefan-Boltzmann) while the other takes definitions, identification and history; swap to check any multi-step calculation.
Building the binder
Notes are unlimited, so organize for speed rather than volume:
- A formula page with units for every equation in this guide, and the constants , , , Wien's constant, and water's , and .
- Conversion tables for temperature and energy units.
- The history table with one-line contributions.
- A process table (what is constant, what is zero, the P-V shape) and labeled diagrams of the Carnot, Otto and Diesel cycles.
- A labeled phase diagram for water and one for CO₂.
- The Condensed facts at the end of this guide as a front-of-binder summary, followed by the reference tables for specific heats, conductivities, expansion coefficients and latent heats.
- Your device calibration graphs and tables, tabbed by height and Heating Time, kept separate from the test notes so the device partner can find them in seconds.
Time management
Bank quick definition and identification questions first. For calculations, write down the given values converted to kelvin, joules, kilograms and pascals before choosing a formula; most lost points are unit slips. Leave long multi-part derivations (Division C) for the end.
Common pitfalls
Using Celsius in absolute-temperature formulas
The ideal gas law, Carnot efficiency, entropy and Stefan-Boltzmann all need kelvin. Only temperature differences can stay in Celsius. Part II scoring is the opposite: it uses °C throughout.
Confusing heat with temperature
A question asking "how much heat" wants joules. Temperature only tells you the direction heat will flow.
Forgetting the phase change
When ice is warmed past 0 °C or water past 100 °C, add the term. The temperature stays flat while it happens.
Mixing up conductivity and specific heat
High thermal conductivity moves heat quickly (metals); high specific heat stores a lot of heat per degree (water). They answer different questions.
Sign conventions in the first law
Check whether is work done by or on the system. A wrong sign gives a that is too large or too small by .
Expecting 100% efficiency
Only a cold reservoir at 0 K would give a Carnot efficiency of 100%, and the third law says you cannot reach it.
Studying the wrong history list
The 2027 outline names Kelvin, Black, Joule, Carnot, Planck, Clausius, Boltzmann and Maxwell. Older practice tests also ask about steam-engine inventors such as Savery, Newcomen and Watt; these are useful background but are not on the 2027 list.
Touching the device
Adjusting a cover or nudging the cup during the Heating Time wipes out 50 of the 100 points. Hands off once the lamp is on.
Converting a temperature difference with the offset
A change of 40 °F is a change of 22 C° (divide by 1.8), not 4.4 °C. Add or subtract 32 or 273.15 only for actual temperatures, never for differences.
Assuming all the ice melts
In a mixing problem with ice, first compare the heat available from the warm parts (cooling to 0 °C) with the heat needed to melt all the ice. If the ice wins, the answer is 0 °C with some ice left.
Using the wrong R or the wrong molar-mass unit
goes with Pa and m³; goes with atm and L. In , must be in kg/mol (0.032 for O₂, not 32).
Calling an adiabatic free expansion isentropic
Isentropic means reversible and adiabatic. A free expansion or a throttling is adiabatic but irreversible, so entropy rises.
Reading COP like an efficiency
A coefficient of performance above 1 is normal (a refrigerator moves more heat than the work it uses). An engine efficiency above the Carnot limit is impossible.
Treating "spontaneous" as "fast"
Spontaneous means the process can happen without outside work; it says nothing about rate. A system's entropy can fall in a spontaneous process if the surroundings' entropy rises more.
How tournaments test this
The public archive holds 1,279 Thermodynamics questions from two earlier seasons (labeled 2017-18 and 2018-19): 934 tagged Division C, 315 Division B and 30 tagged for both. The practice bank holds 4,533 questions, mostly from 2017 to 2019: about 400 exported from these archive tests, about 600 from a 2025 import of tests the archive also holds, and about 3,500 from older tournament tests the archive does not have. Those tests were written for earlier rules, so they cover the core topics (temperature, heat transfer, laws, engines) well but rarely touch radiant exitance, blackbody radiation or the 2027 history list, and some ask about topics outside the 2027 outline.
- Format. About 59% of archived questions are multiple choice, 28% free response, 9% numeric, and the rest true/false or select-all.
- Topic tags (overlapping): laws about 43%, heat transfer about 31%, temperature about 23%, engines about 9%, efficiency about 6%.
- What the questions are about (our classification of the in-scope bank questions, by main topic): temperature scales and conversions 12%; gas laws and kinetic theory 7%; specific heat 7%; the four processes and P-V work 6%; history 6%; first law 6%; conduction and insulation 6%; entropy 5%; latent heat and phase changes 5%; Carnot efficiency 5%; units 4.5%; calorimetry 4%; enthalpy 4%; second law 3%; named engine cycles 2%; systems and properties 2%; and 1–2% each for states of matter, radiation, the zeroth and third laws, Stefan-Boltzmann, thermal expansion, phase diagrams, convection, refrigerators and heat pumps, Newton's law of cooling, blackbody radiation and thermometers. About 10% of the bank is outside the 2027 outline, mostly history of people not on the list (Rumford, Fahrenheit, Nernst, Gibbs, Savery) and Gibbs free energy.
- Tasks. About 12% of archived questions ask for a calculation, typically one formula with a short setup; others are identification ("which of the following"), definitions and short explanations.
- Recurring terms. Heat, temperature, energy, entropy, Carnot, efficiency, Kelvin and adiabatic lead the prompts; specific heat, ideal gas, heat capacity, internal energy, heat engine and Carnot cycle are the most common two-word phrases.
- Most common correct answers. Convection, Joule, radiation, conduction, adiabatic, Clausius and specific heat.
The archive reuses a handful of setups: a Carnot engine between two reservoirs, a phase change of water, two masses mixed in a calorimeter, a gas in a piston, and a "which mechanism" heat-transfer scenario. Master those and the 2027 additions (systems and properties, the history list, and the State/National radiation, third-law, entropy and enthalpy topics), and you cover nearly everything a 2027 test can ask.
Test yourself
These questions come from official keys in the public archive and fall inside the 2027 outline; each links to its full test. We re-solved each one.
- 1
You walk outside on a hot summer day, and immediately you feel the heat from the sun's rays on your face. Which of the following is the type of heat transfer you just experienced?
From: University of Texas at Austin Invitational, 2018-19, Division C
Practice more Thermodynamics questions →
- 1
The absolute temperature of an ideal gas is directly proportional to which of the following quantities?
Practice more Thermodynamics questions →
- 1
A bomb calorimeter tests samples under ____ conditions.
From: University of Texas at Austin Invitational, 2018-19, Division C
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- 1
Which scientist is responsible for the concept of the infamous “perfect” engine?
From: University of Georgia Invitational, 2018-19, Division C
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- 1
A sample of an ideal gas is heated and its Kelvin temperature doubles. If the root-mean-square speed of its molecules was originally v, what is the new root-mean-square speed?
From: Cypress Falls Invitational 2017-18, Division C
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- 1
Which of the following is not a factor in determining the rate of thermal conductivity of a material?
From: Forsyth Invitational, Division C
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- 1
In a system undergoing adiabatic compression, what are the values of internal energy and heat if work done on the system is 500 J?
From: Ladera Vista Invitational 2018, Division B
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- 1
James Joule worked in what occupation?
From: Solon Invitational 2018, Division C
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Condensed facts
Key factsConversions and constants
- ; ; ; −40 °C = −40 °F; differences: 1 K = 1 C° = 1.8 F° = 1.8 R°.
- 1 cal = 4.184 J; 1 Cal = 1 kcal; 1 BTU ≈ 1,055 J; 1 kWh = 3.6 MJ; 1 W = 1 J/s; 1 hp ≈ 746 W; 1 erg = 10⁻⁷ J; 1 L·atm = 101.3 J.
- 1 atm = 101,325 Pa = 760 mmHg = 14.7 psi; 1 L = 10⁻³ m³; 1 gal = 3.785 L.
- = 8.314 J/(mol·K) = 0.08206 L·atm/(mol·K); = 1.38 × 10⁻²³ J/K; = 6.022 × 10²³; = 5.67 × 10⁻⁸ W/(m²·K⁴); Wien = 2.898 × 10⁻³ m·K; = 6.626 × 10⁻³⁴ J·s.
- Water: = 4,186 J/(kg·K) = 1 cal/(g·°C); ice ≈ 2,100; steam ≈ 2,000; = 334 kJ/kg (6.01 kJ/mol); = 2,256 kJ/kg (40.7 kJ/mol); densest at 4 °C; triple point 273.16 K, 611.7 Pa; critical point 647 K, 22.1 MPa.
- CO₂: triple point −56.6 °C, 5.11 atm; sublimes at −78.5 °C at 1 atm; critical point 31.0 °C, 72.8 atm.
| Quantity | Formula | Units and notes |
|---|---|---|
| Sensible heat | in K or °C | |
| Latent heat | Temperature constant | |
| Mixture | Check ice melts first | |
| Expansion | , , | α, β in 1/K |
| Conduction | ; ; | US R = 5.678 × SI R |
| Convection | : still air 2–25 | |
| Radiation | ; | Kelvin |
| Wien | m·K | λ in m, T in K |
| Planet | Earth 255 K | |
| Newton cooling | ||
| Ideal gas | ; | Kelvin |
| Kinetic theory | ; | in kg/mol |
| Heat capacities | = 3/2 R (mono), 5/2 R (di); ; = 1.67, 1.40 | always |
| First law | ( by gas) | Cycle: |
| Isobaric work | Pa × m³ = J | |
| Isothermal work | ||
| Adiabatic | , const; | |
| Engine | Any engine | |
| Carnot | Kelvin; any substance | |
| Otto | = compression ratio | |
| Refrigerator / heat pump | ; | |
| Clausius-Clapeyron | in J/mol | |
| Entropy | ; ; ; | J/K |
| Enthalpy | ; ; | exothermic |
| Phase rule | Triple point |
| Process | Constant | P-V shape | |||
|---|---|---|---|---|---|
| Isothermal | 0 | Hyperbola | |||
| Adiabatic | 0 | Steep curve | |||
| Isobaric | Horizontal | ||||
| Isochoric | 0 | Vertical | |||
| Free expansion | — | 0 | 0 | 0 | Not drawable |
| Throttling | 0 | — | — | Not drawable |
| Cycle | Steps | Use |
|---|---|---|
| Carnot | 2 isotherms + 2 adiabats | Ideal limit |
| Otto | 2 adiabats + 2 isochores | Gasoline |
| Diesel | 2 adiabats + isobar (in) + isochore (out) | Diesel |
| Brayton | 2 adiabats + 2 isobars | Jet, gas turbine |
| Stirling | 2 isotherms + 2 isochores | Regenerative engine |
| Rankine | Pump, boiler, turbine, condenser | Steam plants |
| Refrigeration | Compressor, condenser, expansion valve, evaporator | Fridge, AC, heat pump |
| Scientist | Remember |
|---|---|
| Black | Latent heat, specific heat, heat ≠ temperature (1760s) |
| Carnot | Reflections on the Motive Power of Fire (1824); father of thermodynamics; ideal engine |
| Joule | Mechanical equivalent of heat, paddle wheel (1843–1850); brewer; first law |
| Kelvin | Absolute scale (1848); second-law statement (1851); coined "thermodynamics" |
| Clausius | Second law (1850); entropy (1854, named 1865); mean free path |
| Maxwell | Speed distribution (1860); demon (1867); Theory of Heat (1871) |
| Boltzmann | (on tombstone); derived law (1884) |
| Planck | Blackbody law, quanta (1900); Kelvin-Planck statement; Nobel 1918 |
Key factsLaws and quick facts
- 0th: thermal equilibrium is transitive (thermometers). 1st: (no energy from nothing). 2nd: heat flows hot → cold; no 100% engine; . 3rd: for a perfect crystal at 0 K; 0 K unreachable.
- Conduction needs contact; convection needs a fluid; radiation needs no medium. Thermos: vacuum (conduction, convection) + silvering (radiation).
- Good absorber = good emitter (Kirchhoff). Shiny = low ε. Blackbody ε = 1.
- State functions: . Path functions: .
- Intensive: . Extensive: .
- Entropy rises: melting, boiling, subliming, more gas moles, mixing, expansion, heating.
- ΔH > 0 endothermic (melting, boiling, cold packs); ΔH < 0 exothermic (combustion, freezing, hand warmers). for elements in standard states.
- Isentropic = reversible + adiabatic. Quasi-static = slow, through equilibrium states. Joule-Thomson: constant .
References and further reading
- Science Olympiad, 2027 rules manuals (Division B and C, Thermodynamics) and the event scoring spreadsheet: https://www.soinc.org
- OpenStax, University Physics Volume 2, chapters on temperature and heat, kinetic theory, the first law, and the second law and entropy (free online): https://openstax.org/details/books/university-physics-volume-2
- OpenStax, Chemistry 2e (thermochemistry, enthalpy, phase diagrams, gas laws): https://openstax.org/details/books/chemistry-2e
- NIST, constants and SI definitions (Boltzmann constant, Stefan-Boltzmann constant, kelvin): https://physics.nist.gov/cuu/Constants/
- NIST Chemistry WebBook, thermophysical properties of water: https://webbook.nist.gov/chemistry/fluid/
- HyperPhysics (Georgia State University), heat and thermodynamics pages, including blackbody radiation and Stefan-Boltzmann: http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/thermcon.html
- SciOly Wiki, Thermodynamics (event summary from past seasons): https://scioly.org/wiki/index.php/Thermodynamics
- Practice more: the Scio.ly test archive has public Thermodynamics tests from earlier seasons.